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3 years ago

Solve for a.What is the first step in solving for a?

Mathematics

1 answer:

tamaranim1 [39]3 years ago

3 0

The first step would be to add 27 to both sides

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What is the value of the expression 4x−y/2y x when x = 3 and y = 3? −3 1 9 18

ziro4ka [17]

(4x - y)/(2y + x) when x = 3 and y = 3 is
(4(3) - 3)/(2(3) + 3) = (12 - 3)/(6 + 3) = 9/9 = 1

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3 years ago

Thee questionn is beloww

Phantasy [73]

Given:

$m\angle ABC=60$

To find:

The $m\angle ADC$ .

Solution:

In circle B, $\angle ABC$ is central angle and $\angle ADC$ is inscribed angle from two points A and C.

According to central angle theorem, central angle is always twice of inscribed angle.

$m\angle ABC=2(m\angle ADC)$ [Central angle theorem]

$60=2(m\angle ADC)$

Divide both sides by 2.

$\dfrac{60}{2}=m\angle ADC$

$30=m\angle ADC$

Therefore, $m\angle ADC=30$ .

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3 years ago

3.75<br>divided by 25<br>round off to the nearest rand

sattari [20]

Answer:

0.15 is the answer

Step-by-step explanation:

7 0

2 years ago

Sketch the graph by hand using asymptotes and intercepts, but not derivatives. Then use your sketch as a guide to producing grap

Arisa [49]

The local minima of $f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$ are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)

<h3>How to determine the local minima?</h3>

The function is given as:

$f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$

See attachment for the graph of the function f(x)

From the attached graph, we have the following minima:

Minimum = (-1.5, 0)

Minimum = (7.980, 609.174)

The above means that, the local minima are

(x, f(x)) = (-1.5, 0) and (7.980, 609.174)