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Marizza181 [45]
3 years ago
8

If a boy lifts a mass of 6kg to a height of 10m and travels horizontally with a constant velocity of 4.2m/s, calculate the work

done? Explain your answer.
Physics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

Explanation:

W = mgh = 6(9.8)(10) = 588 J

The horizontal motion has no work associated with it as no potential energy or kinetic energy increases occur.

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1) c. 2 m/s

Explanation:

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v=\lambda f

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v is the speed

\lambda is the wavelength

f is the frequency

For the wave in this problem,

f = 4 Hz

\lambda=0.5 m

So, the speed is

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2)  a. 2.8 m/s

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T is the tension in the string

\mu is the linear mass density

In this problem, we have:

T=2 \cdot 4 N=8 N (final tension in the rope, which is twice the initial tension)

\mu = 1 kg/m --> mass density of the rope

Substituting into the formula, we find

v=\sqrt{\frac{8 N}{1 kg/m}}=2.8 m/s

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