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EastWind [94]
2 years ago
15

A laser is shone through a double slit and a particular interference pattern is observed on a screen some distance away. If the

separation between the openings is increased, the distance between the fringes will
Physics
1 answer:
Grace [21]2 years ago
5 0

If the separation between the openings in a laser is increased, then the distance between the interference fringes decreases

<h3>What is Interference fringe ?</h3>

Interference fringe refers to bands caused by different lights which can be found in phase or not each other.

  • Distances between laser fringes are short which is due to light wavelength.
  • The interference fringes can be estimated by knowing slit separation and wavelength.

In conclusion, if the separation between the openings in a laser is increased, then the distance between the interference fringe decreases

Learn more about Interference fringe here:

brainly.com/question/14264436

#SPJ4

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One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
svet-max [94.6K]

Given:

• Mass, m = 0.200 mg

,

• Speed, v = 3.00 x 10³ m/s

,

• Time, t = 6.00 x 10^⁻⁸ s.

Let's calculate the force exerted.

Using the inpulse-momentum theroerm, we have:

impulse = change in momemntum

Where:

Impulse = force x time

change in momentum = mass x velocity.

Thus, we have:

F\times6.00\times10^{-8}=(0.200\times10^{-6})\times(3.00\times10^3)

Let's solve for the force F:

\begin{gathered} F=\frac{(0.200\times10^{-6})(3.00\times10^3)}{6.00\times10^{-8}} \\  \\ F=10000N \end{gathered}

Therefore, the force exterted is 10000 N.

ANSWER:'

10000 N

4 0
1 year ago
Which image illustrates refraction
photoshop1234 [79]

Answer:

it loaded and it is C. buddy sorry about that :)

4 0
4 years ago
Read 2 more answers
12. Suppose a person uses a mechanical iack to lift half the weight of a car with a
Likurg_2 [28]

a) The force that must be applied is 73.5 N

b) The actual efficiency is 82 %

Explanation:

a)

Since the jack is 100% efficient, all the input work is converted into output work. So we can write:

W_{in} = W_{out}\\F_{in} d_{in} = F_{out} d_{out}

where:

F_{in} is the input force applied on the jack

d_{in} is the arm of the input force

F_{out} is the output force applied on the jack

d_{out} is the arm of the output force

Here we have:

F_{out}=\frac{mg}{2}= \frac{(1200 kg)(9.8 m/s^2)}{2}=5880 N is the output force (half the weight of the car)

d_{in} = 40.0 cm = 0.40 m is the arm of the input force

d_{out} = 5.0 mm = 0.005 m is the arm of the output force

Solving for F_{in}, we find the force that must be applied in input to lift the car:

F_{in} = \frac{F_{out}d_{out}}{d_{in}}=\frac{(5880)(0.005)}{0.40}=73.5 N

b)

The efficiency of the jack is given by the ratio between the output work and the input work:

\eta = \frac{W_{out}}{W_{in}}=\frac{F_{out}d_{out}}{F_{in}d_{in}}

where we have:

F_{out}=5880 N is the output force (half the weight of the car)

d_{in} = 40.0 cm = 0.40 m is the arm of the input force

d_{out} = 5.0 mm = 0.005 m is the arm of the output force

Here we are told that the input force this time is

F_{in}=90.0N

Substituting into the equation, we find the new efficiency of the jack:

\eta = \frac{(5880)(0.005)}{(90.0)(0.40)}=0.82

Which means an efficiency of 82%.

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8 0
4 years ago
Identical particles, each with energy E, are incident on the following four potential energy
amid [387]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

3 0
3 years ago
Propane (c3h8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below. c3h8 5o2 → 3
ahrayia [7]

The amount of oxygen will be 22.29 gm required to produce 37.15 g co₂.

<h3>What is a chemical reaction?</h3>

One or more compounds, known as reactants, are transformed into one or more distinct substances, known as products. Such a process is known as a chemical reaction.

Given reaction;

\rm C_3h_8 +5O_2 }\rightarrow  3CO_2 +4H_2O

The quantity of oxygen is x and the quantity of carbon dioxide is y then the ratio of their composition is found as;

5x=3y

5x=37.15

x=3×37.15/5

x=22.29 gm

Hence the amount of oxygen will be 22.29 gm

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3 0
2 years ago
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