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Tems11 [23]
3 years ago
7

A student mixes two substances in a large beaker. After two hours, the student sees that the substances have separated again.

Physics
1 answer:
S_A_V [24]3 years ago
7 0

The full question is found in the image attached

Answer:

Densities

Explanation:

When we talk about density, one of the things that come to our mind is actually how heavy something is.

If i have substances that possess different densities, i will notice that i can not really mix them because they will separate and the heavier substance will be at the bottom while the lighter substance will be at the top.

Hence the two substances separated due to difference in density.

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A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 70
JulijaS [17]

Answer:

a = 580 m/s^2

Explanation:

Given:

- Distance for accelerated throw s_a = 70 cm

- Angle of throw Q = 30 degrees

- Distance traveled by the javelin in horizontal direction x(f) = 75 m

- Initial height of throw y(0) = 0

- Final height of the javelin y(f) = -2 m

Find:

What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

Solution:

- Compute initial components of the velocity:

                                             V_x,i = V*cos(30)

                                             V_y,i = V*sin(30)

- Use second equation of motion in horizontal direction:

                                          x(f) = x(0) + V*cos(30)*t

                                            75 = 0 + V*cos(30)*t

                                              t = 75 /V*cos(30)

- Use equation of motion in vertical direction:

                                     y(f) = y(0) + V_y,i*t + 0.5*g*t^2

Subs the values:

                      -2 = 0 + V*sin(30)*75/V*cos(30) - 4.905*(75/Vcos(30))^2

                           -2 = 75*tan(30) - 4.905*(5625/V^2*cos^2(30))

                           V^2 = 4.905*5625 / (2 + 75*tan(30))*cos^2(30)

                                                V^2 = 812.0633

                                                 V = 28.5 m/s

- Use the third equation of motion in the interval of the throw:

                                            V^2 = U^2 + 2*a*s_a

                                               28.5^2 = 2*a*0.7

                                                a = 580 m/s^2

         

     

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