Answer: please see attached work.
Explanation: please see attached work. Assuming 500 sheets of paper = 20 lb. (typicical value).
1 mile. Is this a joke lol
Force required to move a block is 1.615 N
Given:
mass of block = m = 150 pounds = 68 kg
distance = d = 5 ft = 1.52 metres
time = t = 8 sec
To Find:
force required to move the block
Solution: Force is defined as product of mass and acceleration and it's unit is N or Newton.
Velocity = displacement/ time = 1.52 / 8 = 0.19 m/s
Acceleration = velocity/time = 0.19/8 =
0.023 m/s^2
Force = mass x acceleration = 68x0.023 = 1.615 N
Hence, force required to move the block is 1.615 N
Learn more about Force here:
brainly.com/question/12970081
#SPJ4
To do this you want to solve for one variable at a time. So we want to cancel out a variable. Lets cancel x. I will multiply the first equation by the number 4 to get 4y=4x-16.
Now lets solve equation 2 for y, giving
-3y=-4x+3 now add equation 1 to equation 2
Y =-13
Now plug that back in to either
-13=x-4
X=-9
So the answer is (-9,-13)
Answer:
Explanation:
Given that,
The magnitude of magnetic field, B = 0.55 T
The radus of the loop, r = 43 cm = 0.43 m
The current in the loop, I = 5.8 mA = 0.0058 A
We need to find the magnetic moment of the loop. It is given by the relation as follows :
Put all the values,
So, the magnetic moment of the loop is equal to
.
