Answer:
490.5 m
Explanation:
we can use the formula s = ut + ½at^2
s= displacement (height of tower)
initial velocity u = 0 m/s
acceleration a = take 9.81 ms-2 (acceleration due to gravity, which is a constant. depending on the given instructions of the question, it may not be exactly 9.81. Some take 10, some take 9.80665)
time t =10s
s = 0t + 1/2 (9.81)(10)^2
s = 490.5 m
Answer: 
The equation that relates the period 
of a body that orbits a greater body in space with the distance 
between both bodies is:
(1)
Where;
is the mass of the Black Hole (the value we want to find)
is the Gravitational Constant and its value is 
is the distance from the Black Hole to the Star S2 (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit).
is the orbital period of the Star S2
At this point, note we have to transform the units of 
from years 
to seconds:
is the orbital period of the Star S2 in seconds
If we want to find the mass of the black hole, we have to express equation (1) as written below and substitute all the values:
(2)
(3)
(3)
Finally we have the mass of the black hole:
The spheres that lost most of their gases are the terrestrial planets.
Edit: The terrestrial planets are also known as the inner planets or rocky planets, so if you have multiple choice options or you learnt a different term, pick that instead.
Answer:
I think it's B it can not be C or D because it has nothing to do with chemical energy
Answer:
Explanation:
From the question we are told that:
Height 
Length
Mass 
Final speed 
Generally the equation for Potential Energy P.E is mathematically given by
Therefore
Initial potential energy
Generally the equation for Kinetic Energy K.E is mathematically given by
Therefore
Final kinetic energy
Generally the equation for Work_done is mathematically given by
Therefore
