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Scrat [10]
3 years ago
11

The duration of a photographic flash is related to an RC time constant, which is 0.200 µs for a certain camera. (a) If the resis

tance of the flash lamp is 0.0410 Ω during discharge, what is the size (in µF) of the capacitor supplying its energy? µF (b) What is the time constant (in s) for charging the capacitor, if the charging resistance is 650 kΩ? s
Physics
1 answer:
Alecsey [184]3 years ago
5 0

Explanation:

It is given that,

The time constant of RC circuit, \tau=0.2\ \mu s=0.2\times 10^{-6}\ s

(a) The resistance of the flash lamp is 0.0410 Ω

We know that the relation between the resistance and time constant is given by :

\tau=R\times C

C=\dfrac{\tau}{R}

C=\dfrac{0.2\times 10^{-6}}{0.0410}

C=4.87\times 10^{-6}\ F

(b) If he value of resistance, R=650\ k\Omega=650\times 10^3\ \Omega

\tau=R\times C

\tau=650\times 10^3\times 4.87\times 10^{-6}

\tau=3.16\ s

Hence, this is the required solution.

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Using diagram differentiate between solenoid and a toroid
damaskus [11]

The Toroid is form when you have wound conductor around circular body. In this case you have magnatic field inside the core but you dont have any poles because circular body dont have ends. This can be used where you want minimum flux leakage and dont need magnatic poles. i.e. toroidal inductor, toroidal transformer.


The Solenoid is forn when you wound conductor around body with limb. In this case magnatic field creates two poles N and S. Solenoids have little bit flux leakage. This used where you want magnatic poles and flux leakage is not an issue. i.e. relay, motors, electromagnates.

1 == toroid


2= solenoid


3 0
3 years ago
A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
ser-zykov [4K]

Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

                       = 8.17 N/m

The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

5 0
3 years ago
Read 2 more answers
How many watt hours will 3-155amp hour 12 volt batteries wired in a parallel configuration produce?
Ede4ka [16]

Answer:

B 5580 W•hr

Explanation:

A Watt is a Volt times an Amp

3(12 V(155 A•hr)) = 5580 W•hr

4 0
3 years ago
there are 5 influencing factors that may affect participation rate in physical activity. can you name them?
Stella [2.4K]
Demographic Barriers, Occupation, Age, Obesity, <span>
Psychological Barriers</span>
6 0
3 years ago
BRAINLIEST AND MAY DOUBLE POINTS!!!
raketka [301]

Given that:

 Energy of bulb  (Work ) = 30 J,

 Time (t) = 3 sec

The power consumption =  ?

 We know that, Power can be defined as rate of doing work

              Power (P) = Work(Energy supplied) ÷ time

                               = 30 ÷ 3

                              = 10 Watts

<em> The power consumption is 10 W.</em>


3 0
3 years ago
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