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defon
2 years ago
5

Is Cardiovascular Fitness the same as Anaerobic Exercise/Fitness?

Physics
1 answer:
oksano4ka [1.4K]2 years ago
7 0

Answer:

Cardiovascular or cardio exercise refers to exercise that strengthens the cardiovascular system. The term Aerobic just means in the presence of oxygen, and aerobic exercise refers to exercise that you perform long enough to require oxygen.

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Calculate the average distances the car and the washer traveled from the top of the track. Record the average in Table A of your
Romashka-Z-Leto [24]
The answer for both is 247 cm
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2 years ago
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Water waves of wavelength 4m are produced by two generators S1 and S2.
Vaselesa [24]
A is not the correct answer because the amplitude and oscillation and there is 1/2 A in oscillation
8 0
1 year ago
Just these 2 question. I have no idea what it's asking..​
Murljashka [212]

Answer: did you get the answers?

Explanation:

5 0
2 years ago
roblem 10: In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following p
miskamm [114]

Answer:

W= -2.5 (p₁*0.0012) joules

Explanation:

Given that p₀= initial pressure, p₁=final pressure, Vi= initial volume=0 and Vf=final volume= 6/5 liters where p₁=p₀ then

In adiabatic compression, work done by mixture during compression is

W= \int\limits^f_i {p} \, dV  where f= final volume and i =initial volume, p=pressure

p can be written as p=K/V^γ where K=p₀Vi^γ =p₁Vf^γ

W= \int\limits^f_i {K/V^} \, dV

W= K/1-γ ( 1/Vf^γ-1 - 1/Vi^γ-1)

W=1/1-γ (p₁Vf-p₀Vi)

W= 1/1-1.40 (p₁*6/5 -p₀*0)  

W= -2.5 (p₁*6/5*0.001)   changing liters to m³

W= -2.5 (p₁*0.0012) joules

3 0
2 years ago
A proton initially at rest is accelerated by a uniform electric field. The proton moves 5.62 cm in 1.15 x 10^-6 s. Find the volt
krok68 [10]

Answer:

49.85 V

Explanation:

u = 0, s = 5.62 cm, t = 1.15 x 10^-6 s

Let the electric field is E and voltage is V.

Use second equation of motion

s = ut + 1/2 a t^2

5.62 x 10^-2 = 0 + 0.5 a x (1.15 x 10^-6)^2

a = 8.5 x 10^10 m/s^2

m x a = q x E

E = m x a / q

E = (1.67 x 10^-27 x 8.5 x 10^10) / (1.6 x 10^-19)

E = 887.19 V/m

V = E x s

V = 887.19 x 5.62 x 10^-2 = 49.85 V

4 0
3 years ago
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