Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =

y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< AnswerProblem Two
Remember that

y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer
Answer:
20
Step-by-step explanation:
Pythagorean Theorem: a^2 + b^2 = c^2
21^2 + b^2 = 29^2
441 + b^2 = 841
Subtract 441 on both sides to get b^2 = 400
Take the square root of both sides to get b = 20
N = 33 and m = 6 substitute in the values in place of the variables to get 33 - 5*(6). distribute the five to get 33 - 30 =3. the answer is three
4ax+12-3ax=25+3a
Ax+12=25+3a
Ax=25-12+3a
Ax=13+3a
X=13/a+3