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Vlad1618 [11]
4 years ago
5

If I launch a 13 kg rocket straight up at 48 m/s

Physics
2 answers:
BigorU [14]4 years ago
6 0
Sorry that makes no sense
Monica [59]4 years ago
4 0
It makes a boomer and I think it’s 61kg
You might be interested in
a hot piece of copper is placed in an insulated cup. what is the final temperature of the water and copper?
slavikrds [6]

Answer:

Option C. 30°C.

Explanation:

The following data were obtained from the question:

Mass of water (Mw) = 0.5 Kg

Specific heat capacity of water (Cw) = 4.18 KJ/Kg°C

Initial temperature of water (Tw1) =

22°C

Change in temperature (ΔT) = T2 – Tw1 = T2 – 22°C

Mass of copper (Mc) = 0.5 Kg

Specific heat capacity of copper (Cc) = 0.386 KJ/kg°C

Initial temperature of copper (Tc1) = 115°C

Change in temperature (ΔT) = T2 – Tc1 = T2 – 115°C

Final temperature (T2) =..?

Note: Both the water and the piece copper will have the same final temperature and the heat will be zero since the water will cool the piece of copper.

Thus, we can determine the final temperature of the water and copper as follow:

Q = MwCwΔT + McCcΔT

0 = 0.5 x 4.18 x (T2 – 22) + 0.5 x 0.386 x (T2 – 115)

0 = 2.09 (T2 – 22) + 0.193 (T2 – 115)

0 = 2.09T2 – 45.98 + 0.193T2 – 22.195

Collect like terms

2.09T2 + 0.193T2 = 45.98 + 22.195

2.283T2 = 68.175

Divide both side by the coefficient of T2 i.e 2.283

T2 = 68.175/2.283

T2 = 29.8 ≈ 30°C

Therefore, the final temperature of water and copper is 30°C.

8 0
3 years ago
The position x of a particle moving along x axis varies with time t as x = Asin(wt) , where A and w are constants . The accelera
Elodia [21]

Let's see

\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)

Now we know the formula of acceleration

\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)

\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2

  • From eq(1)

\\ \rm\Rrightarrow \alpha=-x\omega^2

Or

\\ \rm\Rrightarrow \alpha=-\omega^2x

6 0
2 years ago
Read 2 more answers
All matter is made up of particles called
Bad White [126]

Answer:

atoms and molecules

Explanation:

as opposed to being continuous or just including particles). On the following page, the idea is stated as one of four concepts in Dalton's theory: “All matter is composed of tiny, indivisible particles called atoms”

6 0
3 years ago
Read 2 more answers
A fillet weld has a cross-sectional area of 25.0 mm2and is 300 mm long. (a) What quantity of heat (in joules) is required to acc
HACTEHA [7]

Answer:

77362.56 J

163730.28571 J

Explanation:

A = Area = 25 mm²

l = Length = 300 mm

K = Constant = 3.33\times 10^{-6}

\eta = Heat transfer factor = 0.75

f_m = Melting factor = 0.63

T = Melting point of low carbon steel = 1760 K

Volume of the fillet would be

V=Al\\\Rightarrow V=25\times 300\\\Rightarrow V=7500\ mm^3=7500\times 10^{-9}\ m^3

The unit energy for melting is given by

U_m=KT^2\\\Rightarrow U_m=3.33\times 10^{-6}\times 1760^2\\\Rightarrow U_m=10.315008\ J/mm^3

Heat would be

Q=U_mV\\\Rightarrow Q=10.315008\times 7500\\\Rightarrow Q=77362.56\ J

Heat required to weld is 77362.56 J

Amount of heat generation is given by

Q_g=\dfrac{Q}{\eta f_m}\\\Rightarrow Q_g=\dfrac{77362.56}{0.75\times 0.63}\\\Rightarrow Q_g=163730.28571\ J

The heat generated at the welding source is 163730.28571 J

7 0
4 years ago
An object is traveling at a constant velocity of 10m/s for 4 seconds. What is its acceleration?
saw5 [17]

Answer:

<h2>The answer is 2.5 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula

acceleration =  \frac{velocity}{time}  \\

From the question

time = 4 s

velocity = 10 m/s

So we have

acceleration =  \frac{10}{4}  =  \frac{5}{2}  \\

We have the final answer as

<h3>2.5 m/s²</h3>

Hope this helps you

5 0
4 years ago
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