Answer: D. decreasing the temperature
Explanation:
Answer:
The net torque on the square plate is 2.72 N-m.
Explanation:
Given that,
Side = 0.2 m
Force 
Force 
Force 
We need to calculate the torque due to force F₁
Using formula of torque


Put the value into the formula


We need to calculate the torque due to force F₂
Using formula of torque


Put the value into the formula


We need to calculate the torque due to force F₃
Using formula of torque


Put the value into the formula


We need to calculate the net torque on the square plate



Hence, The net torque on the square plate is 2.72 N-m.
We define acceleration as the rate of change of the velocity
Thus, if you have positive velocity and positive acceleration, your <u>speed increases.</u>
If you have positive velocity and negative acceleration, your speed decreases.
Now you get the idea, we will see that the correct option is graph 1.
We know that the car moves towards the right (let's define this as "the car has positive velocity") and we also know that te car is slowing down constantly (thus the acceleration needs to be negative and constant).
By looking at the graphs, the only one with these properties is graph 1.
If you want to learn more, you can read:
brainly.com/question/12550364
I think the answer would be c
If any current is PRODUCED in an individual home, like with
a windmill or solar panels, it is direct current (DC).
The current SUPPLIED to homes by the local utility company
is alternating current (AC).