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Bas_tet [7]
3 years ago
8

3. Use the balanced chemical equation from the last question to solve this situation: You combine 0.5 grams of Na2CO3 with exces

s CaCl2. How many grams of NaCl would you expect this reaction to produce? Show all work below. g
Chemistry
1 answer:
kramer3 years ago
8 0

Answer:

<em><u>0.27 g</u></em>

Explanation:

The reaction equation:

Na_{2} CO_{3} + CaCl_{2} → 2NaCl + CaCO_{3}

106g of Na2CO3 - 1 mole

0.5g of Na2CO3 = 0.5 ÷ 106

= 0.0047 moles.

1 mole of NaCl - 58.5

⇒ 0.0047 moles = 0.0047 × 58.5

= 0.27g.

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Answer:

Sugar is a polar compound , in the solid state of it Hydrogen bond strongly binds the molicules of sugar together. Being a non polar solvent and low polarity difference between Cl and C atom C—Cl bond in CCl4 is unable to form hydrogen bond. That's why sugar can't be soluble in CCl4.

Explanation:

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6. The modern view of the atom has come a long way from that of a solid, indestructible sphere
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3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15
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Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}

(b) Mass of H

\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

\text{Moles of C = 1400  mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016  + 16.00) u  = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00  \approx 5

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

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Vinvika [58]

Answer: b. The waste generated is hazardous and must  be disposed of.

c. Nuclear material can be spilled into the ocean  if reactors are near the coast.

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3 years ago
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