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Bas_tet [7]
3 years ago
8

3. Use the balanced chemical equation from the last question to solve this situation: You combine 0.5 grams of Na2CO3 with exces

s CaCl2. How many grams of NaCl would you expect this reaction to produce? Show all work below. g
Chemistry
1 answer:
kramer3 years ago
8 0

Answer:

<em><u>0.27 g</u></em>

Explanation:

The reaction equation:

Na_{2} CO_{3} + CaCl_{2} → 2NaCl + CaCO_{3}

106g of Na2CO3 - 1 mole

0.5g of Na2CO3 = 0.5 ÷ 106

= 0.0047 moles.

1 mole of NaCl - 58.5

⇒ 0.0047 moles = 0.0047 × 58.5

= 0.27g.

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Q.89

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3 years ago
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melisa1 [442]
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P/ T = k
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