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Bas_tet [7]
3 years ago
8

3. Use the balanced chemical equation from the last question to solve this situation: You combine 0.5 grams of Na2CO3 with exces

s CaCl2. How many grams of NaCl would you expect this reaction to produce? Show all work below. g
Chemistry
1 answer:
kramer3 years ago
8 0

Answer:

<em><u>0.27 g</u></em>

Explanation:

The reaction equation:

Na_{2} CO_{3} + CaCl_{2} → 2NaCl + CaCO_{3}

106g of Na2CO3 - 1 mole

0.5g of Na2CO3 = 0.5 ÷ 106

= 0.0047 moles.

1 mole of NaCl - 58.5

⇒ 0.0047 moles = 0.0047 × 58.5

= 0.27g.

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UkoKoshka [18]

Answer:

1. a

Explanation:

2. c

7 0
3 years ago
Read 2 more answers
the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of t
Levart [38]

Answer:

m = 50.74 kg

Explanation:

We have,

Initial temperature of water is 20 degrees Celsius

Final temperature of water is 46.6 degrees Celsius

Heat absorbed is 5650 J

It is required to find the mass of the sample. The heat absorbed is given by the formula ad follows :

Q=mc\Delta T

c is specific heat of water, c = 4.186 J/g°C

So,

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{5650}{4.186\times (46.6-20)}\\\\m=50.74\ kg

So, the mass of the sample is 50.74 kg.

8 0
3 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
2 Points
pishuonlain [190]

Answer:

B

Explanation:

Boyle was known for rejecting Aristotle's theory basing it on the four elements (earth, air, fire, water).

4 0
3 years ago
Xg 4Na + 15g 02 → 70g 2Na20
aleksley [76]

Answer: 43.125g

Explanation:4Na+ O2=2Na2O

Molar mass: 23. 32. 62. React.mass: 92.

6 0
3 years ago
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