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3 years ago

PLSSSSS HELP I HAVE BEEN STUCK ON THIS FOR THE PAST HOUR!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

$- 6 \sqrt{2}$

Step-by-step explanation:

simplify

$\sqrt{28800}$

$120 \sqrt{2}$

then

-0.05 × 120 = -6

then we have our answer

-6√2

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4x when x = 3/4 (I really need help)

hoa [83]

3/4 is 0.75 as a decimal so 4 x 0.75 = 3

8 0

3 years ago

What is the surface area of the cylinder? Express the answer in terms of pi

Sholpan [36]

Bonjour,

answer ≈ 522.92

working
A= 2πrh+2πr^2
=2 x π x 4 x 18+2 x π x 4^2
≈552.92031

4 0

3 years ago

Plz help me with this question I don't understand it!!

Sav [38]

9t-7t-t^2
2t-t^2

Hope this helps :)

3 0

3 years ago

Jake can cut and split a cord of firewood in 9 fewer hours than Dwight can. When they work together, it takes them 6 hours. How

Luba_88 [7]

Answer:

18 hours for Dwight, 9 hours for Jake

Step-by-step explanation:

If J is the time it takes for Jake working alone, and D is the time it takes for Dwight working alone, then:

J = D − 9

Working together, Jake's speed plus Dwight's speed equals 1 cord per 6 hours.

1 / J + 1 / D = 1 / 6

Solve the system of equations by substituting for J:

1 / (D − 9) + 1 / D = 1 / 6

Multiply both sides by D − 9.

1 + (D − 9) / D = (D − 9) / 6

Multiply both sides by D:

D + D − 9 = D (D − 9) / 6

Simplify and solve:

2D − 9 = (D² − 9D) / 6

12D − 54 = D² − 9D

0 = D² − 21D + 54

0 = (D − 3) (D − 18)

D = 3 or 18

Since J = D − 9, D must be greater than 9. So D = 18 and J = 9.

That means it takes Dwight 18 hours working alone, and it takes Jake 9 hours working alone.

3 0

3 years ago

The average monthly cell phone bill was reported to be $50.07 by the U.S. Wireless Industry. Random Sampling of a large cell pho

zalisa [80]

Answer:

The null and alternative hypotheses are:

$H_{0}:\mu= 50.07$

$H_{a}:\mu>50.07$

Under the null hypothesis, the test statistic is:

$t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }$

Where:

$\bar{x} = 52.86$ is the sample mean

$s=7.0132$ is the sample standard deviation

$n=10$ is the sample size

$\therefore t=\frac{52.86-50.07}{\frac{7.0132}{\sqrt{10}} }$

$=1.26$

Now, the right tailed t critical value at 0.05 significance level for df = n-1 = 10-1 = 9 is:

$t_{critical}=1.833$

Since the t statistic is less than the t critical value at 0.05 significance level, therefore,we fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the average phone bill has increased.

4 0

3 years ago