The principle of a lever is when two equal forces act in opposite directions and ultimately come to a state of equilibrium if distanced properly
i hope that helps?^
According to Newton laws of motion,
F = m*a
Here, m = 1,560 Kg
a = 1.30 m/s²
Substitute their values,
F = 1,560 * 1.30
F = 2028 N ~ 2030 N [ Closest value ]
In short, Your Answer would be Option C
Hope this helps!
Explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.

d = ![\frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20%5Ctimes%2075%20%5Ctimes%20%280.7%2B0.15%2B0.15%29%20-%2060%20%5Ctimes%200.15%20-%20252%20%5Ctimes%200.15%20%5Ctimes%202%5D%7D%7B252%7D)
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.
Explanation:
It is given that,
The acceleration of the toboggan, 
Initial speed of the toboggan, u = 0
We need to find the distance covered by the toboggan. Using the second equation of motion as :

At t = 1 s


At t = 2 s


At t = 3 s


Hence, this is the required solution.
Answer:
I will explain the concept of magnetic field and how it can be calculated.
Explanation:
The formula for magnetic field at the center of a loop is given as
B = μ
I / 2R
where B is the magnetic field
R is the radius of the loop
I is the current
and μ
is the magnetic permeability of free space which is a constant 4π ×
newtons/ampere²
If the magnetic field at the center of the loop is 0, then μ
I = 0
I = 0 which means there will be no current flow in the loop.