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Vedmedyk [2.9K]
2 years ago
9

An electric current in a copper wire is produced by the motion of which of the following particles? a. copper atoms b. neutrons

c. protons d. electrons
Physics
1 answer:
algol [13]2 years ago
5 0

Answer:

electrons

Explanation:

Because electric current is flowed due to the presence of free electrons.

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Physics multiple choice
Aleksandr-060686 [28]

10. b

11.d

12. b

13.e

I hope this helps

3 0
3 years ago
Read 2 more answers
Calculate the total resistance in a parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω. (Hint: When converting to a decim
natta225 [31]

Answer:

Total resistance = 0.92Ω

Explanation:

For parallel connected resistors we have effective resistance

                 \frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+.....

Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.

That is

             R₁ = 2Ω

             R₂ = 3Ω

             R₃ = 4Ω

Substituting

             \frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\\\frac{1}{R_{eff}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\\\\\frac{1}{R_{eff}}=\frac{6+4+3}{12}\\\\R_{eff}=\frac{12}{13}=0.92ohm

Total resistance = 0.92Ω

6 0
3 years ago
Can someone tell me the answer for both of these pleaseeee i need it asap!!! i will give brainlist!!
inessss [21]

Answer:

1/ decreases

2/ yes;

In general there is no relationship, and any combinations of frequencies and amplitudes are allowed.

Explanation:

Explanation for 1/ - please see the picture attached below

6 0
3 years ago
How can Climate Change impact the formation of Hurricanes?
Orlov [11]
Climate change may affect tropical cyclones in a variety of ways: an intensification of rainfall and wind speed, a decrease in overall frequency, an increase in frequency of very intense storms and a poleward extension of where the cyclones reach maximum intensity are among the possible consequences
4 0
2 years ago
Read 2 more answers
What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?
Alisiya [41]
We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
\Delta V = I R
where
\Delta V is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and R=330 \omega, so the potential difference is
\Delta V = IR=(4.00 A)(330 \omega)=1320 V
7 0
3 years ago
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