I suppose the answer would be C. Kepler's three laws talk about planetary orbit.
The higher the voltage in series, the brighter the bulb gets. so removing one battery from the circuit causes a reduction in the brightness of the bulb.
hope this helps
Answer: time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Explanation:
For an RC Charging circuit
Where Vs
Vc = Vs (1 - e^(-t/RC))
Vc/Vs = 1 - e^(-t/RC)
-t/RC = ln(1 - Vc/Vs)
t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)
Where ;
Vc = voltage across the capacitor
Vs = voltage supply
t = charging time = 2.5ms
k = RC = time constant.
Vc/Vs = 0.35
To calculate the time constant k;
k = -t/ln(1- Vc/Vs)
k = -2.5/ln(1-0.35)
k = 5.80ms
time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Answer: The most likely identity of the substance is iron.
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed=
Joules
m= mass of substance = 11.9 g
c = specific heat capacity = ?
Initial temperature of the water = 
= 25.0°C
Final temperature of the water = 
= 45.0°CChange in temperature ,
Putting in the values, we get:
The specific heat of 0.45 is for iron and thus the substance is iron.
