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son4ous [18]
3 years ago
5

Water is heated to boiling and water vapor (steam) is released. Chemical change or physical change?

Chemistry
1 answer:
Vlad [161]3 years ago
6 0
Physical because it is still H2O
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Exposure of silver Chloride to sunlight for a long<br>duration turns grey due to​
Tema [17]

Answer:

Exposure of silver chloride to sunlight for a long duration turns grey due to​ photolytic decomposition i.e decomposition in the presence of sunlight.

Explanation:

When silver chloride, AgCl is exposed to sunlight for a long time, it will undergo decomposition as the sunlight provides sufficient energy needed to decomposed the salt, AgCl to metallic silver and chlorine gas. This can be seen in the equation below:

2AgCl —> 2Ag + Cl2

5 0
3 years ago
If you have 10cm of snow with a volume of 40mL and a density of 0.5 g/mL how many inches of rain is this?
Lelu [443]

Density is the mass of compound divided by its volume can be shown as follows:

d = 0.5 g /mL = m /V = m /40 = 0.5

m = 20 g

40 mL of snow having 20 g of mass calculated from density.

Now, 10 cm of snow = 3.93 inches = 20 g  

As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.

10 inches rain = 11 inches snow

3.93 inches of snow produced by  

= (3.93 * 10) /11 = 3.57 inches rain.

Thus, 3.57 incehs of rain produces by 10 cm snow.

4 0
2 years ago
Uranium has 146 neutrons; therefore its mass number is which of the following?
Vilka [71]
Its <span>234or238  hope dis helped</span>
5 0
3 years ago
Read 2 more answers
The variable in an experiment that is changed on purpose
DiKsa [7]
The answer is Independent Variable
4 0
3 years ago
What is the final concentration of cl- ion when 250 ml of 0.20 m cacl2 solution is mixed with 250 ml of 0.40 m kcl solution? (as
serious [3.7K]

CaCl2 and KCl are both salts which dissociate in water when dissolved. Assuming that the dissolution of the two salts are 100 percent, the half reactions are:

<span>CaCl2 ---> Ca2+  +  2 Cl-</span>

KCl ---> K+ + Cl-

Therefore the total Cl- ion concentration would be coming from both salts. First, we calculate the Cl- from each salt by using stoichiometric ratio:

Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles Cl / 1 mole CaCl2)

Cl- from CaCl2 = 0.1 moles

 

Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1 mole KCl)

Cl- from KCl = 0.1 moles

 

Therefore the final concentration of Cl- in the solution mixture is:

Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)

Cl- = 0.2 moles / 0.5 moles

<span>Cl- = 0.4 moles             (ANSWER)</span>

6 0
3 years ago
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