Based on the concentration of the solutions, the increase in volume is as follows:
- the volume of the 20% (m/v) starch increases
- the volume of the 10% (m/v) albumin increases
- the volume of the 5% (m/v) sucrose increases
<h3>What is osmosis?</h3>
Osmosis is the movement of water molecules from a region of low solute concentration to a region of high solute concentration through a semipermeable membrane.
The movement of water molecules in the solution pairs is as follows:
- the volume of the 20% (m/v) starch increases because water moves in from the 10% (m/v) starch solution.
- the volume of the 10% (m/v) albumin increases because water moves in from the 2% (m/v) albumin
- the volume of the 5% (m/v) sucrose increases because water moves in from the 0.5% (m/v) sucrose.
Therefore, the increase in volume depends on the concentration ofvthe solutions.
Learn more about osmosis at: brainly.com/question/2625460
This force is opposing in nature .it resists object velocity .
Answer:
7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.
Explanation:
Let the volume of 10% acid solution used to make the mixture = x L
So, the volume of 30% acid solution used to make the mixture = y L
Total volume of the mixture = <u>x + y = 30 L .................. (1)
</u>
For 10% acid solution:
C₁ = 10% , V₁ = x L
For 30% acid solution :
C₂ = 30% , V₂ = y L
For the resultant solution of sulfuric acid:
C₃ = 25% , V₃ = 30 L
Using
C₁V₁ + C₂V₂ = C₃V₃
10×x + 30×y = 25×30
So,
<u>x + 3y = 75 .................. (2)
</u>
Solving 1 and 2 we get,
<u>x = 7.5 L
</u>
<u>y = 22.5 L</u>
AB+XY->AY+XB
We know that the answer would be KCl because of the switching that takes place during a double displacement reaction. Just like Zn and MnO4 switched and combined, the remaining elements, K and Cl, will combine.
We know that the answer is simply KCl because both K and Cl have an ion of only +/-1, meaning when they cross, no suffixes are made, since their ions are only 1.
For example, if you combined Mg with Cl, you would get MgCl2, because Mg has an ion of +2.
I hope this helps!
Cl2(g) -------> Cl-(aq) + ClO-(aq)
2e- + Cl2(g) -------> 2Cl-(aq) [reduction]
4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation]
______________________________________...
2OH-(aq) + Cl2(g) --------> Cl-(aq) + ClO-(aq) + H2O(l)