Answer:
Equilibrium shifts to produce more reactant
Explanation:
- <em>Le Châtelier's principle</em> <em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
- When more product is added to the solution:
<em>This will increase the concentration of the products side, so the reaction will be shifted to the lift side (reactants side) to suppress the increase in the concentration of Products.</em>
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<em>So, the right choice is: Equilibrium shifts to produce more reactant</em>
The atomic orbitals of the central atom mix to form hybrid orbitals are one s and three p.
<h3>Which atomic orbitals are used to form hybrid orbitals?</h3>
Pauling supposed that in the presence of four hydrogen atoms, the s and p orbitals form four equivalent combinations which he called hybrid orbitals.
<h3>How many bonds does PF5?</h3>
Phosphorus pentafluoride has 5 regions of electron density around the central phosphorus atom (5 bonds, no lone pairs).
The resulting shape is a trigonal bipyramidal in which three fluorine atoms occupy equatorial and two occupy axial positions.
Learn more about PF5 here:
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brainly.com/question/1565926</h3><h3 /><h3>#SPJ4</h3>
Answer:
Explanation:
You can view more details on each measurement unit: molecular weight of Copper(I) Oxide or grams The molecular formula for Copper(I) Oxide is Cu2O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Copper(I) Oxide, or 143.0914 grams.
Answer:
<em>Lower vapor pressures of a substance has an obvious effect on a</em> <em>boiling point</em>. <em>The</em> <em>freezing point </em><em>the rate at which the solid melts is equal to the rate which freezes. </em>
Explanation:
<em>In practice, small differences between these quantities can be observed. It is difficult, if not impossible, to heat a solid above its melting point because the heat </em>
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<em>Hope this helps (: </em>