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3 years ago

Write the equilibrium constant: Pb3(PO4)2(s) = 3Pb2+ (aq) + 2PO2 (aq)

Chemistry

1 answer:

kicyunya [14]3 years ago

7 0

Answer:

Kc = [Pb²⁺]³.[PO₄³⁻]²

Explanation:

Let's consider the following reaction at equilibrium.

Pb₃(PO₄)₂(s) ⇄ 3 Pb²⁺(aq) + 2 PO₄³⁻(aq)

The concentration equilibrium constant is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Kc = [Pb²⁺]³.[PO₄³⁻]²

This equilibrium constant is known as the solubility product of Pb₃(PO₄)₂.

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From the following data, calculate the average bond enthalpy for the NOH bond: NH3(g) ¡NH2(g) 1 H(g) ¢H° 5 435 kJ/mol NH2(g) ¡NH

Sphinxa [80]

Answer:

The average bond enthalpy for the N-H bond is 392 kJ/mol.

Explanation:

$NH_3(g) \rightarrow NH_2(g) +1 H(g),\Delta H^o_{1}= 435 kJ/mol$ ..[1]

$NH_2(g) \rightarrow NH(g) + H(g),\Delta H^o_{2}= 381 kJ/mol$ ..[2]

$NH(g) \rightarrow N(g)+ 1 H(g),\Delta H^o_{3}= 360 kJ/mol$ ..[3]

On adding [1] , [2] and [3] , we get:

$NH_3(g) \rightarrow N(g) +3H(g),\Delta H^o_{4}= ?$

$\Delta H^o_{4}=\Delta H^o_{1}+\Delta H^o_{2}+\Delta H^o_{3}$

$= 435 kJ/mol+381 kJ/mol +360 kJ/mol = 1,176 kJ/mol$

There three bonds N-H bond sin ammonia. Then average bond enthalpy of single N-H bond is :

$\Delta H^o_{N-H}=\frac{1,176 kJ/mol}{3}=392 kJ/mol$

The average bond enthalpy for the N-H bond is 392 kJ/mol.

4 0

3 years ago

How does Barium obey the octet rule when reacting

Kryger [21]

Answer:

it gives up electrons B. because the bond between the electrons is not very strong due to how few of them there are

Explanation:

7 0

3 years ago

Read 2 more answers

In every balanced chemical equation, each side of the equation has the same number of _____.

Ber [7]

The correct answer is option d, that is, atoms of the element.

As the atoms are neither destroyed nor created in a chemical reaction, the sum of the mass of the products in a reaction must be equivalent to the sum of the mass of the reactants.

The chemical reactions must be balanced, they must exhibit a similar number of atoms of each element on both the sides of the equation. As a consequence, the mass of the reactants must be equivalent to the mass of the products of the reaction.

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3 years ago

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It was found that 2.35 g of a compound of phosphorus and chlorine contained 0.539 g of phosphorus. What are the percentages by m

igor_vitrenko [27]

Answer:

Explanation:

P = 2.35g

Cl= 0.539 g

% MASS = mass of X/ mass of a compound

% mass of P = 2.35 / (2.35+ 0.539) = 81.34%

% mass of Cl = 0.539 /(2.35+ 0.539) = 18.66 %

3 0

4 years ago

N 2H 4 + H202 N2 + H 20

Degger [83]

Answer:

N2 + H20

Explanation:

chemical equation balancer

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3 years ago