Answer: True the bicarbonate mixture can help save time and few routine.
Explanation:
For the purpose of making dialysate for hemodialysis patient therapies a bicarbonate mixing and delivering systems designed to prepare a liquid sodium bicarbonate formulation comes in handy.
Certain systems like the SDS unit also allow for the transfer and distribution of acid concentrate solutions. We also provide stand-alone acid concentrate delivery systems using a variety of holding tanks and delivery methods.
A challenge for hemodialysis providers is to properly provide bicarbonate solution in a cost effective manner. Preparation and disinfection can be time-consuming and labor intensive.
Bicarbonate however can corrode certain metals and painted surfaces leaving your preparation area encrusted and grimy.
Furthermore, if not mixed properly, bicarbonate can negatively affect the dialysate solution.
The answer to the above is true the bicarbonate mixture can help save time and few routine.
Chloroplasts is an important part in the process of photosynthesis in some organisms. The chloroplast absorbs the energy in sunlight and uses it to produce sugars.
Answer:
The rate of the forward reaction and the rate of the reverse reaction are equal
The concentrations of the reactants and products no longer change.
Explanation:
The equilibrium state is a state of rest or motion of chemical system.
These are some of the condition for dynamic equilibrium of a system:
the systems must be involved in reversible chemical reactions.
the rate of forward reaction is equal to that of the reverse process.
the system offers no resistance to any change in any of the factors.
there is no change in concentration of each of the species in equilibrium with respect to time.
We can see that a system in equilibrium clearly identifies with the chosen options.
Answer:
0.0835 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
0.0250 L of 0.105 M HCl react.
0.0250 L × 0.105 mol/L = 2.63 × 10⁻³ mol
Step 3: Calculate the reacting moles of NaOH
The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 2.63 × 10⁻³ mol = 2.63 × 10⁻³ mol.
Step 4: Calculate the molarity of NaOH
2.63 × 10⁻³ moles of NaOH are in 0.0315 L of solution.
M = 2.63 × 10⁻³ mol / 0.0315 L = 0.0835 M
If a ball is running down a ramp, why is it that when you change the height of the ramp, the ... of the ramp, then you will increase the acceleration of a ball which rolls down the ramp.
