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Yakvenalex [24]

3 years ago

9

Five-digit locker combinations are assigned using the digits 1–9. In how many ways can the combinations be formed if no digit ca

n be repeated

1 answer:

Orlov [11]3 years ago

4 0

Answer:

15, 120

Step-by-step explanation:

9P4

.............................................................................................

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ZanzabumX [31]

Answer:

1. 1 cup of concentrate would use 7.5 cups of water.

2. 10 cups of concentrate would use 75 cups of water.

Step-by-step explanation:

Because 1/3 cup of concentrate is mixed with 2 1/2 cups of water, to find how much water one cup of concentrate would use, you would have to multiply both 1/3 and 2 1/2 (2.5) by 3. Then, you get 1 cup of concentrate equals 7 1/2 (7.5).

To find the answer to the next question, simply multiply by 10.

7 0

3 years ago

Find the slope between the two points: (9,9) and (12,15)

grandymaker [24]

The slope formula is $\frac{Y2-Y1}{X2-X1}$ . For the two points, $(x,y)$ . You can pick any of the Y and X from these two points, but only once. $\frac{9-15}{9-12}$ = $\frac{-6}{-3}$ = 2 or $\frac{15-9}{12-9}$ = $\frac{6}{3}$ = 2 and both will equal to. The answer for the slope is 2.

3 0

2 years ago

Read 2 more answers

What is the area of the shaded region?

ella [17]

33cm

Because add all of them then subtract then do the parenthasees and you get 33

3 0

2 years ago

A tourist calculated that if he walks to the railroad station with a speed of 4 mph, he’ll miss the train by half an hour, but

nevsk [136]

You have to do speed over time to find out the distance the tourist will have to cover. (Speed multiplied by time= distance)

7 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago