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Serjik [45]
3 years ago
9

Help quick im on a test i need anwer If x:6 as 3:9, then x is equal to what

Mathematics
1 answer:
dsp733 years ago
4 0

Answer: x=2

Step-by-step explanation:

To find out what x equals you have to find the rate of change. You do this by dividing 9 from 6 this will give you 1.5. Then you divide 3 by 1.5 then you get 2

Hope this helps :)

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Tony buys 2 boxes of chocolates. One is 4 in. 7 in. 8 in. And 8 in. 5 in. 6 in. Which box has the larger volume?
Rufina [12.5K]

Answer:

Second box

Step-by-step explanation:

Volume (of the box) = length * width * height

Volume of first box is: 4 * 7 * 8 = 224

Volume of second box is: 8 * 5 * 6 = 240

Since 224 < 240, the volume of the second box has the larger value.

4 0
3 years ago
The city has an average of 13 days of rainfall for April.
zhenek [66]

Using the Poisson distribution, we have that:

  • There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.
  • There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.
  • There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

For this problem, the mean is given as follows:

\mu = 13

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0

P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003

P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

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Answer:

es 21

Step-by-step explanation:

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What is the board feet of lumber if it has a 2-inch thickness, 3-inch width and length is 7ft?
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Answer:

B. 3.5

Step-by-step explanation:

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2×3=6inch

7ft=84

6×84=504

504inch³=3.5board ft

#gamer

3 0
3 years ago
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