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lys-0071 [83]
3 years ago
7

Please Help! Look at Screenshot for question.

Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

C

Step-by-step explanation:

A modified box plot does not include the outliers in the whiskers, instead they are points outside of the whiskers

5,25,33,34,34,37,37,40,42,45,45,46,46,49,73

This data has 2 outliers 5 and 73 so we have 2 choices for a modified box plot D or D

The lowest value outside of the outliers is 25 , so C would be the logical choice

D has the lower end of the whisker too close to the outlier

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In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
3 years ago
Solve for k:<br> 310 – (30 x 7) = 5 x k
tester [92]

Answer:

k=20

Step-by-step explanation:

ph*tomath (the app) is your friend btw because this would be really easy to solve using that but

solve for k:

simplify the left side as 310-210 then =100

so 100=5k

divide by 5 and k=20

7 0
3 years ago
How many interior angles does a triangle have
Aleonysh [2.5K]
There are 3 interior angles.
7 0
3 years ago
Read 2 more answers
What is the quotient? Negative StartFraction 3 over 8 EndFraction divided by negative one-fourth
anyanavicka [17]

Answer:

\dfrac{3}{2}

Step-by-step explanation:

We are given 2 fractions.

1st fraction is Negative StartFraction 3 over 8

i.e.

-\dfrac{3}{8}

2nd fraction is negative one-fourth

i.e.

-\dfrac{1}{4}

We have to find the quotient when 1st fraction is divided by 2nd fraction.

<u>Definition</u> of quotient is given as:

Quotient is the result obtained when one number is divided by other number.

-\dfrac{3}{8} \div -\dfrac{1}{4} \text{ is to be calculated.}

\div is converted to \times and the 2nd fraction is reversed i.e.

if the fraction is \frac{p}{q} it becomes \frac{q}{p} and the sign \div is changed to \times.

Solving above:

-\dfrac{3}{8} \times -\dfrac{4}{1}\\ \text {Multiplication/Division of 2 negative number gives a positive number}\\\Rightarrow \dfrac{3}{2}

So, the quotient is \frac{3}{2}.

6 0
3 years ago
Plant B is 6 2/3 inches tall. and C is 4 4/15 inches tall. Complete the sentences and show your reasoning
artcher [175]

Answer:

Plant C is <u>0.64</u> times as tall as Plant B

Plant C is <u>2.4 inches</u> shorter than Plant B

Step-by-step explanation:

Plant B is 6 2/3 inches tall. Plant B is 20/3 inches tall.

Plant C 4 4/15 inches tall. Plant C is 64/15 inches tall.

a.) Plant C is shorter than Plant B = \frac{64}{15} \times \frac{1}{\frac{20}{3} }  = \frac{64}{15} \times\frac{3}{20}  = \frac{16}{25} = 0.64 times.

b.) Plant C is shorter than Plant B by = \frac{20}{3}  - \frac{64}{15}  = \frac{100}{15}  - \frac{64}{15}  = \frac{100 -64}{15}  = \frac{36}{15} = 2\frac{2}{5} = 2.4 inches

3 0
3 years ago
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