You should have put a picture of the question so ppl could see what your talkin bout
The set of values of the independent variable(s) for which a function or relation is defined. Typically, this is the set of x-values that give rise to real y-values. Note: Usually domain means domain of definition, but sometimes domain refers to a restricted domain.
Answer:
f⁻¹(x) = x - 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Functions
- Function Notation
- Inverse Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = x + 3
<u>Step 2: Find</u>
- Swap: x = y + 3
- [Subtraction Property of Equality] Isolate <em>y</em>: x - 3 = y
- Rewrite: f⁻¹(x) = x - 3
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Answer:
x = 6
Step-by-step explanation:
The sum of segments is used:
EF +FG = EG
3x +(5x +16) = 11x -2 . . . . substitute given expressions
8x +18 = 11x . . . . . . . . add 2
18 = 3x . . . . . . . . subtract 8x
6 = x . . . . . . divide by 3
The value of the variable is 6.
__
<em>Check</em>
The segment lengths are ...
EF = 3x = 3·6 = 18
FG = 5x+16 = 5·6 +16 = 46
EG = 11x -2 = 11·6 -2 = 64 = 18+46 . . . answer is correct
