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ELEN [110]
3 years ago
11

What is a + 1/10 = 5/10 (need fast)

Mathematics
2 answers:
posledela3 years ago
7 0
I would say 2/5 would be the answer
Snezhnost [94]3 years ago
5 0
2/5 would be the answer to that question.
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mai has 36$ to spend on movie tickets each movie ticket cost 4.50$ how many ticket can she buy multiplication problem
-Dominant- [34]

Answer:

8

Step-by-step explanation:

Mai has $36 and each movie ticket is $4.50.

You wanna divide 36 by 4.50 to find out how much tickets she can purchase which is 8.

6 0
2 years ago
A hiker is at an elevation of meters from sea level. Which statement would explain the hiker’s movement if they want to get back
ElenaW [278]

Answer:

It would be 92 up

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different
irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0
3 years ago
When a child is more than two standard deviations underweight for his or her age, the child is suffering from a condition called
SOVA2 [1]
Stunting is the impaired growth and development that children experience from poor nutrition, repeated infection, and inadequate psychosocial stimulation. Children are defined as stunted if their height-for-age is more than two standard deviations below the child growth standard
3 0
3 years ago
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