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8_murik_8 [283]
2 years ago
15

Menthol is a crystalline substance with a peppermint taste and odor. When 0.533 g of menthol is dissolved in 25.0 g of cyclohexa

ne, the freezing point of the solution is lowered by 2.84 ∘C. Look up the freezing point and f constant for cyclohexane in the Colligative Constants table. Calculate the molar mass of menthol.
Chemistry
1 answer:
Bess [88]2 years ago
8 0

Answer: The molar mass of menthol is 156.15 g/mol

Explanation:

Depression in freezing point is given by:

\Delta T_f=K_f\times m

\Delta T_f=T_f^0-T_f=2.84^0C = Depression in freezing point

K_f = freezing point constant = 20.8^0C/m

m= molality

\Delta T_f=K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (cyclohexane)= 25.0 g = 0.025 kg  

Molar mass of solute (menthol) = ?

Mass of solute (menthol) = 0.533 g

2.84^0C=20.8\times \frac{0.533}{xg/mol\times 0.025}

x=156.15g/mol

The molar mass of menthol is 156.15 g/mol

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Answer:

They are called homogenous mixtures. If you put sand into a glass of water, it is considered to be a mixture. You can always tell a mixture, because each of the substances can be separated from the group in different physical ways. You can always get the sand out of the water by filtering the water away.

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3 years ago
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What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?​
allochka39001 [22]

Answer:

1^{f} =187.7 \frac{J}{kg}

Explanation:

SO in order to calculate the specific latent heat of fusion, you need to remember the formula:

1^{f} =\frac{Q}{m}

Where 1^{f} representes the specific latent heart of fusion.

Q represents the heat energy added, usually represented in kJ

m represents the mass of the object, in kg.

Now that we have our formula we just have to put our values into the formula:

1^{f} =\frac{Q}{m}

1^{f} =\frac{863kJ}{4.6kg}

1^{f} =187.7 \frac{J}{kg}

SO our answer would be 1^{f} =187.7 \frac{J}{kg}

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3 years ago
You are playing a game “will it float?” In this game, you are given a large, square can of tuna. If you know the density of wate
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3 years ago
Type the correct answer in the box.
IgorLugansk [536]

Answer:

a= <em>In scientific notation</em>

6.96000×10⁵ Km

b =<em>In  expanded notation</em>

0.00019 mm

Explanation:

Given data:

Radius of sun = 696000 Km

size of bacterial cell = 1.9 ×10⁻⁴ mm

Radius of sun in scientific notation = ?

Size of bacterial cell in expanded notation = ?

Solution:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

. The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

Radius of sun:

696000 Km

<em>In scientific notation</em>

6.96000 × 10⁵ Km

The expanded notation is standard notation of writing the numerical values which is normal way. The numbers are written as they are, without the power of 10.

Size of bacterial cell:

1.9 ×10⁻⁴ mm

<em>In  expanded notation</em>

1.9/ 10000 = 0.00019 mm

3 0
3 years ago
A rigid vessel contains water at 0.15 MPa (at 25 °C). The vessel is heated to the critical point of water. Calculate the fractio
pishuonlain [190]

Answer:

0.8078 Kg

Explanation:

Pressure of water = 0.15 MPa = 1.5 bar

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From the ideal gas equation

P×V= m×R×T

Let us assume volume = 1 m^3

1.5 x 105 x 1 = m x 287 x 647

m= 0.8078 kg

the fraction of mass of liquid at 25°C.

4 0
3 years ago
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