Answer:107.1 g, 124.1 g
Explanation:
The equation of the reaction is;
Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)
Hence;
For Al2S3
Number of moles= reacting mass/molar mass
Number of moles = 158g/150gmol-1 =1.05 moles
If 1 mole of Al2S3 yields 3 moles of H2S
1.05 moles of Al2S will yield
1.05 × 3/1 = 3.15 moles
Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g
For water
Number of moles of water = 131g/18gmol-1= 7.3 moles
6 moles of water yields 3 moles of H2S
7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S
3.65 moles × 34 gmol-1 =124.1 g
Answer:
C. Yes, because they have a definite composition.
Explanation:
<h2><u><em>
PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
Answer:
It would produce ethane (CH₃CH₃)
Explanation:
Ethylmagnesium bromide (CH₃CH₂MgBr) is a Grignard's reagent.
It is a highly reactive substance, and as any alkylmagnesium bromide
(R-CH₂MgBr) it reacts with water to produce an alkane (R-CH₃). R stands for any carbon structure bonded to that functional group.
I believe the answer is C: "<span>It occurs when a hydrogen atom bonds with electropositive atoms."</span>