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liq [111]
3 years ago
15

A rigid vessel contains water at 0.15 MPa (at 25 °C). The vessel is heated to the critical point of water. Calculate the fractio

n of mass of liquid at 25°C.
Chemistry
1 answer:
pishuonlain [190]3 years ago
4 0

Answer:

0.8078 Kg

Explanation:

Pressure of water = 0.15 MPa = 1.5 bar

At critical point of water ,temperature = 647 K=374°C

From the ideal gas equation

P×V= m×R×T

Let us assume volume = 1 m^3

1.5 x 105 x 1 = m x 287 x 647

m= 0.8078 kg

the fraction of mass of liquid at 25°C.

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5 0
3 years ago
A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 84 g of water (with an
laila [671]

The specific heat of metal is c = 3.433 J/g*⁰C.

<h3>Further explanation</h3>

Given

mass of metal = 68.6 g

t metal = 100 °C

mass water = 84 g

t water = 20 °C

final temperature = 52.1  °C

Required

The specific heat

Solution

Heat can be formulated :

Q = m.c.Δt

Q absorbed by water = Q released by metal

84 x 4.184 x (52.1-20)=68.6 x c x (100-52.1)

11281.738=3285.94 x c

c = 3.433 J/g*⁰C.

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A particular tank of oxygen gas contains 785 L at 21°C.If the pressure remains constant,what volume will the gas occupy if the t
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Make sure to list known values on the side. Based on the wording of the question, we know that pressure is constant and moles is constant. You can rearrange the ideal gas equation and solve for the volume.

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