g A chemist combines 59.9 mL of 0.282 M potassium bromide with 15.4 mL of 0.512 M silver nitrate. (a) How many grams of silver b
1 answer:
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, since the potassium bromide and silver nitrate are in a 1:1 mole ratio, the first step is to identify the limiting reactant, by considering the reacting volumes of reactants in order to compute the available moles of potassium bromide and the moles of potassium bromide consumed by the 15.4 mL of 0.512-M solution of silver nitrate:
In such a way, since less moles are consumed than available, we infer that silver nitrate is the limiting reactant, for which the resulting grams of silver bromide (molar mass 187.8 g/mol) result:
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Answer:
1) Maximun ammount of nitrogen gas:
2) Limiting reagent:
3) Ammount of excess reagent:
Explanation:
<u>The reaction </u>
Moles of nitrogen monoxide
Molecular weight:
Moles of hydrogen
Molecular weight:
Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess
1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted
2) <u>Limiting reagent</u>:
3) <u>Ammount of excess reagent</u>:
Answer is: B because it has a lower activation energy.
For all chemical reaction some energy is required and that energy is called activation energy (energy that needs to be absorbed for a chemical reaction to start), activation energy for reaction B is lower that for reaction A.
Catalysis is the increase in the rate of a chemical reaction due to the participation of an additional substance called a catalyst.
Chemical reactions occur faster with a catalyst because they require less activation energy.
