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aleksandr82 [10.1K]
3 years ago
12

Python programmers use the Else statement to run code

Computers and Technology
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

the answer is <u>True</u>

Explanation:

when you use an if statement it has to end with an else statement because the if statement is used to give opinions in a code but if the option doesn't fit the need of the function then the else statement is expected.

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Suppose we wanted to make change for purchases and wanted to use the least number of coins possible. Here is a greedy algorithm:
love history [14]

Answer:

Explanation:

The following code is a Python function that takes in the amount of change. Then it uses division and the modulo operator to calculate the number of coins that make up the changes, using the greatest coin values first.

import math

def amountOfCoins(change):

   print("Change: " + str(change))

   quarters = math.floor(change / 0.25)

   change = change % 0.25

   dimes = math.floor(change / 0.20)

   change = change % 0.20

   pennies = math.floor(change / 0.01)

   print("Quarters: " + str(quarters) + "\nDimes: " + str(dimes) + "\nPennies: " + str(pennies))

5 0
3 years ago
Which icons allows you to add a style to a chart
ZanzabumX [31]
Click on your chart and go under Table Tools, Design... then you should see the different styles. ;)
5 0
3 years ago
These things are commonly found on the front of desktop computer cases:
jok3333 [9.3K]

USB ports, headphone jack/microphone port, and of course, a power button.

3 0
3 years ago
A file named 'input.txt' contains a list of words. Write a program that reads the content of the file one word at a time. Check
Margarita [4]

Answer:

// here is code in java.

import java.io.*;

import java.util.Scanner;

class Main{  

    // function to check a word is palindrome or not

 private static boolean is_Palind(String str1)

 {

     // if length of String is 0 or 1

   if(str1.length() == 0 || str1.length() == 1)

   {

     return true;

   }

   else

   {

       // recursively check the word is palindrome or not

     if(str1.charAt(0) == str1.charAt(str1.length()-1))

     {

       return is_Palind(str1.substring(1,str1.length()-1));

     }

     

     else

     {

       return false;

     }

   }

 }

// driver function

 public static void main(String[] args)

 {// variable to store word

   String word;

   // BufferedWriter object

   BufferedWriter buff_w = null;

   // FileWriter object

   FileWriter file_w = null;

   // Scanner object

   Scanner sc = null;

   try

   {

       // read the input file name

     sc = new Scanner(new File("input.txt"));

     // output file

     file_w = new FileWriter("output.txt");

     // create a buffer in output file

     buff_w = new BufferedWriter(file_w);

     

     // read each word of input file

     while(sc.hasNext())

     {

       word = sc.next();

     // check word is palindrome or not

       if(is_Palind(word))

       {

           // if word is palindrome then write it in the output file

         buff_w.write(word);

         buff_w.write("\n");

       }

     }

     // close the buffer

     buff_w.close();

     // close the input file

     sc.close();

   }

   // if there is any file missing

   catch (FileNotFoundException e) {

     System.out.println("not able to read file:");

   }

   // catch other Exception

   catch (IOException e) {

     e.printStackTrace();

   }

 }

}

Explanation:

Create a scanner class object to read the word from "input.txt" file.Read a word  from input file and check if it is palindrome or not with the help of is_Palind() function.it will recursively check whether string is palindrome or not. If it is  palindrome then it will written in the output.txt file with the help of BufferedWriter  object. This will continue for all the word of input file.

Input.txt

hello world madam

level welcome

rotor redder

output.txt

madam

level

rotor

redder

3 0
3 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
3 years ago
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