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Molodets [167]
2 years ago
11

Which function has an inverse that is also a function? {(–4, 3), (–2, 7), (–1, 0), (4, –3), (11, –7)} {(–4, 6), (–2, 2), (–1, 6)

, (4, 2), (11, 2)} {(–4, 5), (–2, 9), (–1, 8), (4, 8), (11, 4)} {(–4, 4), (–2, –1), (–1, 0), (4, 1), (11, 1)}
Mathematics
2 answers:
KonstantinChe [14]2 years ago
5 0

Answer:  The correct option is

(A) {(–4, 3), (–2, 7), (–1, 0), (4, –3), (11, –7)}.

Step-by-step explanation:  We are given to select the function having an inverse that is also a function.

We know that

a Relation as a set of ordered pairs is a function if each x co-ordinate does not correspond to two different y co-ordinates.

Option (A) : F = {(–4, 3), (–2, 7), (–1, 0), (4, –3), (11, –7)}.

Here, the inverse of F will be

R = {(3, -4), (-2, 7), (0, -1), (-3, 4), (-7, 11)}.

Since no x co-ordinate corresponds to more than one y co-ordinate, so this inverse will be a function.

Option (A) is CORRECT.

Option (B) : F = {(–4, 6), (–2, 2), (–1, 6), (4, 2), (11, 2)}.

Here, the inverse of F will be

R = {(6, -4), (2, -2), (6, -1), (2, 4), (2, 11)}.

Since the x co-ordinate corresponds to three different y co-ordinates (-2, 4 and 11), so this inverse will NOT be a function.

Option (B) is not correct

Option (C) : F =  {(–4, 5), (–2, 9), (–1, 8), (4, 8), (11, 4)}.

Here, the inverse of F will be

R = {(5, -4), (9, -2), (8, -1), (8, 4), (4, 11)}.

Since the x co-ordinate 8 corresponds to two different y co-ordinates (-1 and 4), so this inverse will NOT be a function.

Option (C) is not correct.

Option (D) : F =  {(–4, 4), (–2, –1), (–1, 0), (4, 1), (11, 1)}.

Here, the inverse of F will be

R = {(4, -4), (-1, -2), (0, -1), (1, 4), (1, 11)}.

Since the x co-ordinate 1 corresponds to two different y co-ordinates (4 and 11), so this inverse will NOT be a function.

Option (D) is not correct.

Thus, (A) is the correct option.

DaniilM [7]2 years ago
4 0
(-4,4) because its at the same hold for the other functions
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Hey ! there

Answer:

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In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>

For finding volume of sphere , we need to know its formula . So ,

\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} =  \dfrac{4}{3} \pi r {}^{3} }}}

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\quad \longrightarrow \qquad \: \dfrac{4}{3}  \times 3.14 \times 3 \times 3 \times 3

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\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}}  \times 3.14 \times 3 \times 3 \times  \cancel{3}

We get ,

\quad \longrightarrow \qquad \:4 \times 3.14 \times 9

Multiplying 4 and 3.14 :

\quad \longrightarrow \qquad \:12.56 \times 9

Multiplying 12.56 and 9 :

\quad \longrightarrow \qquad \:    \pink{\underline{\boxed{\frak{113.04  \: unit \: cube}}}} \quad \bigstar

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