Answer:
first, arrange the numbers then classify the number into two like if there are 7 numbers classify into three then the middle one will be the median
Answer:
There are 6 classes we find the median by finding the middle number of the 3rd highest class and 4th highest class, even if this is a decimal.
6/3 = 3+ 0.5
The process would be different if some values are the same values already on the chart total of each class.
ie) 20 31 14 22 20 31
small data like this below you can rearrange
14 20 20 22 31 31
and see that 21 is the correct value
as there are even numbers, so we choose 20 , 22
and select the middle value = 21
Step-by-step explanation:
If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer: x=6 and the angle is 50
Step-by-step explanation:
1. a whole triangle = 180°
2. subtract 70 and 60 to get 50
3. subtract 2 from 50 and get 48
4. divide 48 by 8 and you get 6.
hope this helps :) everyone reading this have a great day!
