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Mrac [35]
3 years ago
7

Plz answer the question

Physics
1 answer:
Vikentia [17]3 years ago
3 0

Answer:

Ray A = Incidence ray

Ray B = Reflected ray

Explanation:

From the law of reflection,

Normal: This is the line that makes an angle of 90° with the reflecting surface.

Ray A is the incidence ray: This is the ray that srikes the surface of a reflecting surface. The angle formed between the normal and the incidence ray is called the incidence angle

Ray B is the reflected ray: This is the ray leaves the surface of a reflecting surface. The angle formed between the reflected ray and the normal is called reflected angle

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Answer:

Explanation:

A unit used to measure a vector quantity is the

c) Newton

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Why does Alpha Centauri appear to be yellow-white?
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3 years ago
Read 2 more answers
A ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. What is the average speed of the
antoniya [11.8K]
Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m

The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²

The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s

The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s

Answer: 12.5 m/s

6 0
2 years ago
A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at
BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

p_{i} = p_{f}

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

v_{1_{i}}: is the initial speed of the car = 40 km/h = 11.11 m/s

v_{2_{i}}: is the initial speed of the lorry = 20 km/h = 5.56 m/s

v_{1_{f}}: is the final speed of the car =?

v_{2_{f}}: is the final speed of the lorry =?    

Since the two vehicles become tightly locked together after the collision v_{1_{f}} = v_{2_{f}}:

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})

v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!  

8 0
2 years ago
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