Answer:
Answer: Kelvin ________________
Answer:
coasting down hill on a bicycle
Explanation:
Coasting down the hill on a bicycle is a typical example of how kinetic energy is being transformed to potential energy in a system.
Kinetic energy is the energy due to the motion of a body, it can be derived using the expression below;
K.E =
m v²
Potential energy is the energy due to the position of a body. It can be derived using;
P.E = mgh
m is the mass
v is the velocity
g is the acceleration due to gravity
h is the height
Now, at the top of the hill, the potential energy is at the maximum. As the bicycle coasts down the potential energy is converted to kinetic energy.
The distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
Velocity is a vector quantity. It has both a direction and a magnitude. Speed is used to calculate the magnitude of velocity. The meter per second is the S.I. unit for this. The units km/h and km/s are additional units. [LT-1] is the dimensional equation for it.
The distance traveled by the object is calculated as the product of the velocity with which it was moving and the time interval for which the distance covered is calculated.
Distance traveled = Velocity × Time
Given in the question
Velocity of the plane = 1200 Km/h
Time Traveled = 2.5 h
Put in the value, we get
Distance traveled = 1200 × 2.5
Distance traveled = 3000 Km
Hence, the distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
LEARN MORE ABOUT VELOCITY HERE:
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Answer:
Wavelength, 
Explanation:
It is given that,
Velocity of an electron, 
Mass of an electron, 
We need to find the wavelength of an electron. It can be calculated using the De- Broglie wavelength as :



So, the wavelength of an electron is
. Hence, this is the required solution.
The charges are the same in absolute value, so the change of potential energy is the same. That means that the change in kinetic energy is also the same. Then:
1 = Ke/Kp = m_e *v_e^2 / m_p * v_p^2, or
v_e/v_p = sqrt( m_p/m_e),
So the speed of the electron will be sqrt( m_p/m_e) times greater than the speed of the proton