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daser333 [38]
3 years ago
14

I can Multiply a 11x6 matric by a 6x7 matrix. The resulting matrix will be ??? Can somebody help me

Mathematics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

The resulting matrix will be 11 * 7

Step-by-step explanation:

Given

Matrices 11 * 6 multiplied by 6 * 7

Required

The dimension of the resulting matrix

When a matrix a * b is multiplies by a matrix b * c, the resulting matrix will be: a * c

In this case:

a * b = > 11 * 6

b * c => 6 * 7

So, the resulting matrix will be:

a * c => 11 * 7

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Solve for x in quadratic equation if x(2x-1)=1 , can you please help me please ​
kumpel [21]

Answer:

x=1 or -1/2

Step-by-step explanation:

The value of x is 1 or -1/2

8 0
3 years ago
What is the mean,median,mode(s) an range if the numbers are 15,30,17,15,24,31,15
Phoenix [80]
The mean is 21.  The median is 15.  The mode is 15.  The range is 16.
7 0
3 years ago
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Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at
Vesnalui [34]
F(x)=x^2/(x-2)(x-1), the degree of the numerator and the degree of the denominator equal and the quotient of their coefficient equal to 1(horizontal asymptote means that the lines approach a certain number when the input approaches positive or negative infinity)
and when plugging in 2 or 1 as input, the output is undefined.
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3c/4 - 2c/4 = 4 (solve with work please)
xxMikexx [17]

Simplifying

2c + 3 = 3c + -4

Reorder the terms:

3 + 2c = 3c + -4

Reorder the terms:

3 + 2c = -4 + 3c

Solving

3 + 2c = -4 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.

3 + 2c + -3c = -4 + 3c + -3c

Combine like terms: 2c + -3c = -1c

3 + -1c = -4 + 3c + -3c

Combine like terms: 3c + -3c = 0

3 + -1c = -4 + 0

3 + -1c = -4

Add '-3' to each side of the equation.

3 + -3 + -1c = -4 + -3

Combine like terms: 3 + -3 = 0

0 + -1c = -4 + -3

-1c = -4 + -3

Combine like terms: -4 + -3 = -7

-1c = -7

Divide each side by '-1'.

c = 7

Simplifying

c = 7

3 0
3 years ago
If PQ=8 and Q lies at -13 where could P be located?
choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first.  )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0
3 years ago
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