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Marizza181 [45]
3 years ago
13

Which element has 1 valence electron in its outer shell and will react with a

Physics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

the element that has 1 valence electron will react with a silicon the answer is B.

Musya8 [376]3 years ago
3 0

Answer: C. Lithium

Explanation: Quizzed

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Which one is better yoga or exercise?
coldgirl [10]

Answer:

Yoga because It brings together physical and mental disciplines to achieve a peaceful body and mind; it helps manage stress and anxiety and keeps you relaxing and exercising just builds muscles

Explanation:

have great day!

8 0
2 years ago
One of the foci for the moon's orbit would be the
suter [353]
The question is oversimplified, and pretty sloppy.

Relative to the Earth . . .
The Moon is in an elliptical orbit around us, with a period of
27.32... days, and with the Earth at one focus of the ellipse.

Relative to the Sun . . .
The Moon is in an elliptical orbit around the Sun, with a period
of 365.24... days, and with the Sun at one focus of the ellipse,
and the Moon itself makes little dimples or squiggles in its orbit
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5 0
3 years ago
Read 2 more answers
Is this statement true or false? Electric currents flow easily through materials that are conductors and through materials that
Alex777 [14]
False because currents do not flow easily through insulators. If it only said conductors, then it would be true.
3 0
4 years ago
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Se deja caer una pelota inicialmente en reposo desde una altura de 50m sobre el nivel del suelo. ¿cuanto tiempo requiere para ll
umka2103 [35]

Answer:

a) t = 3.2 s

b) v_{f} = -32 m/s

Explanation:

a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:

t = \sqrt{\frac{2y_{0}}{g}}

En donde:

y_{0}: es la altura inicial = 50 m

g: es la gravedad = 10 m/s²

t = \sqrt{\frac{2y_{0}}{g}} = \sqrt{\frac{2*50 m}{10 m/s^{2}}} = 3.2 s

Entonces, el tiempo requerido para llegar al suelo es 3.2 s.

b) La rapidez de la pelota justo antes del choque es el siguiente:

v_{f} = v_{0} - gt

En donde:

v_{0}: es la velocidad inicial = 0 (dado que se deja caer en resposo)

v_{f} = v_{0} - gt = 0 - 10 m/s^{2}*3.2 s = -32 m/s

Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).

Espero que te sea de utilidad!

6 0
3 years ago
Plz help question in picture
Lostsunrise [7]
I think it's the last one
4 0
3 years ago
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