It depends on how b approaches 0
If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.
On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.
The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.
Answer:
is the slope and
is the y-intercept.
Step-by-step explanation:
The slope-intercept form of a line is given as:

Here, the coefficient of
represents the slope of the line.
The coefficient of
is
and hence the slope.
y-intercept is the value of
for which is
is 0.
Now, if we put
as 0 in the above equation, we get

Therefore, y-intercept is
.
Hence, for the line with slope-intercept form
,
is the slope and
is the y-intercept.
Answer:
fg(x) = 32x²+44x+16
Step-by-step explanation:
fg(x) = f[g(x)]
= f(4x+3)
= 2(4x+3)²-(4x+3)+1
= 2(4x+3)²-(4x+3)+1
= 2(16x²+24x+9)-4x-3+1
= 32x²+44x+16
C = 1.6b
c + b = 442
1.6b + b = 442
2.6b = 442
b = 442 / 2.6
b = 170 <== Boston
c = 1.6b
c = 1.6(170)
c = 272 <== Colorado Springs
Answer:
7
Step-by-step explanation: