What is the surface area of a square pyramid with a base length and slant height of 5 inches?
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Answer:
46
Step-by-step explanation:
With those problems if you are not given a picture is good we draw one.
Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then
m < XVY = m < YVW
2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms
2x-x = 15-7, combine like terms
x = 8
From the picture and the given we see that
m < XVW = m < XVY + m < YVW
m < XVW = 2x+7 + x+15 , combine like terms
m < XVW = 3x + 22, substitute x for 8
m < XVW = 3*8 + 22
m < XVW = 46
Check our work:
m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23
m < YVW = x+15 = 8 +15 = 23
m < XVW = m < XVY + m < YVW = 23+23 =46
