Lu(NO₃)₃ would be the formula for a lutetium nitrate compound, given that the charge of lutetium is the same in both compounds.
From Lu2(CO₃)₃, we can determine the charge of the variable charge transition metal Lu has a charge of 3, as CO₃ has a 2⁻ charge (3⁻² = 6⁻¹, 6/2 = 3). Then, we apply this to nitrate, which has a charge of 1⁻. Balance charges, reduce, and you get Lu(NO₃)₃.
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Nitrates:</u></h3>
With the chemical formula NO⁻₃, nitrate is a polyatomic ion. This ion is found in salts, which are known as nitrates. Fertilizers and explosives frequently contain nitrates as a component. Nearly all inorganic nitrates are water soluble. Bismuth oxynitrate is an illustration of an insoluble nitrate.
Natural compounds called nitrates (or nitrites) can be found in the soil, air, and water. In order to prevent the growth of germs and to improve the flavor and color of food, nitrates are also employed as a food additive.
To view similar questions based on nitrates of different compounds, refer to:
brainly.com/question/5346392
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If a substance is made of pure element, Chances are they're gonna react with one another.
Answer:
C₂H₂ + 3H₂ ⟶ 2CH₄
Explanation:
The initial concentrations are:
[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹
[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹
[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹
2CH₄ ⇌ C₂H₂ + 3H₂
I/mol·L⁻¹: 1.05 0.700 1.858
![Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BC%24_%7B2%7D%24H%24_%7B2%7D%24%5D%5BH%24_%7B2%7D%24%5D%7D%5E%7B3%7D%7D%7B%5Ctext%7B%5BCH%24_%7B4%7D%24%5D%7D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B%200.700%5Ctimes%201.858%5E%7B3%7D%7D%7B1.05%5E%7B2%7D%7D%3D%204.07)
Q > K
That means we have too many products.
The reaction will go to the left to get rid of the excess products.
C₂H₂ + 3H₂ ⟶ 2CH₄
Answer:
Hydrogenation – meaning, to treat with hydrogen – is a chemical reaction between molecular hydrogen and another compound or element, usually in the presence of a catalyst such as nickel, palladium or platinum. The process is commonly employed to reduce or saturate organic compounds
Explanation:
