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MissTica
2 years ago
7

У = 3х - 17 for x it lists 3, 4,5,6 i don’t know what to put for y

Mathematics
1 answer:
Brut [27]2 years ago
7 0

Answer:

x = 3, y = -8

x = 4, y = -5

x = 5, y = -2

x = 6, y = 1

Step-by-step explanation:

You can apply the equation y = 3x - 17 for the different values for x.

x = 3

y = 3(3) - 17

  = 9 - 17

  = -8

x = 4

y = 3(4) - 17

 = 12 - 17

 = -5

x = 5

y = 3(5) - 17

  = 15 - 17

  = -2

x = 6

y = 3(6) - 17

  = 18 - 17

  = 1

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Pls help I'd appreciate it
gayaneshka [121]

Answer:

2)

(2x -5) + (x) + (2x - 3) = 32.

5x-8 = 32.

ii) 5x-8=32

5x= 32+8

5x = 40

x= 40/5

x = 8

iii) 2x -5

2 × 8 -5 = 11.

2x-3

2×8-3

16-3 = 13

x =8

sides of the triangle= 8, 11, 13.

5 0
3 years ago
Math help, thanks for the help. i'm very great full
rodikova [14]

4x +28 and 68 are vertical angles and are equal.

Set them to equal each other to solve for x:

4x +28 = 68

Subtract 28 from each side:

4x = 40

Divide both sides by 4:

x = 40/4

x = 10

4 0
3 years ago
The diagonals of a rhombus are 12 in. and 16 in. long. The length of a side of the rhombus is 10 in. What is the height of the r
iris [78.8K]
If d₁ and d₂ are the lengths of the diagonals, the area is given by
.. A = (1/2)*d₁*d₂
.. A = (1/2)*(12 in)*(16 in)
.. A = 96 in²

If b is the base and h is the height, the area is given by
.. A = b*h
We know the values of A and b, so
.. 96 in² = (10 in)*h
.. (96 in²)/(10 in) = h = 9.6 in

The height is 9.6 in.
3 0
3 years ago
Do not answer ...........
mixas84 [53]

Answer:

sorry abs

Step-by-step explanation:

8 0
3 years ago
find a set of parametric equations of the line the line pases through the point (2,3,4) and is parallel to the xz-plane and the
joja [24]

Answer:

x=2, y=3, z=4+t

Step-by-step explanation:

For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

u= (u_x, u_y, u_z)= (0,0,1)

Or any factor of u but for simplicity let's take the unitary vector.

Then the parametric equations are given by:

x= P_x + u_x t

y= P_y + u_y t

z= P_z + u_z t

Where the point given P=(2,3,4)= (P_x , P_y, P_z)

And then since we have everything we can replace like this:

x= P_x + u_x t 2+ 0*t = 2

y= P_y + u_y t= 3+ 0*t = 3

z= P_z + u_z t = 4+ 1t = 4+t

x=2, y=3, z=4+t

6 0
3 years ago
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