Answer:
2)
(2x -5) + (x) + (2x - 3) = 32.
5x-8 = 32.
ii) 5x-8=32
5x= 32+8
5x = 40
x= 40/5
x = 8
iii) 2x -5
2 × 8 -5 = 11.
2x-3
2×8-3
16-3 = 13
x =8
sides of the triangle= 8, 11, 13.
4x +28 and 68 are vertical angles and are equal.
Set them to equal each other to solve for x:
4x +28 = 68
Subtract 28 from each side:
4x = 40
Divide both sides by 4:
x = 40/4
x = 10
If d₁ and d₂ are the lengths of the diagonals, the area is given by
.. A = (1/2)*d₁*d₂
.. A = (1/2)*(12 in)*(16 in)
.. A = 96 in²
If b is the base and h is the height, the area is given by
.. A = b*h
We know the values of A and b, so
.. 96 in² = (10 in)*h
.. (96 in²)/(10 in) = h = 9.6 in
The height is 9.6 in.
Answer:
sorry abs
Step-by-step explanation:
Answer:

Step-by-step explanation:
For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

Or any factor of u but for simplicity let's take the unitary vector.
Then the parametric equations are given by:



Where the point given 
And then since we have everything we can replace like this:



