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3 years ago

Simplify:

Mathematics

1 answer:

liubo4ka [24]3 years ago

8 0

Answer:

78.5÷3.14=25

56.272×41.2=2318.4064

429×338×712=103241424

447÷513=0.8713450292

Step-by-step explanation:

hope it will help!

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The amount dispensed by a soft-drink dispensing machine has a normal distribution with mean μ and standard deviation 0.191 ounce

nirvana33 [79]

Answer:

The value of mean is $\mu = 15.64$

Step-by-step explanation:

The normal distribution of the soft-drink dispensing machine can be stated statistically like

$X$ ~ $N (\mu ,0.191^2)$

The standard form representation is

$P(X$

Now we need to obtain $\mu$ in such a way that

$P(X>16) = 0.01$

In standard form

Since

$P(Z>16 -\frac{\mu}{0.191} ) = 0.03$

This means

$P(Z$

Now looking at the z-table for probability of 0.99 we obtain 1.88

i.e

$16 - \frac{\mu}{0.191} = 1.88$

Making $\mu\ the \ subject$

$16 - \mu = 1.88 *0.191$

$\mu = 16 -(1.88*0.191)$

$=15.64$

8 0

3 years ago

Evaluate the expression when x = 8 and y = 1.

dimaraw [331]

X / 2y
= 8 / 2( 1 )
= 8 / 2
= 4

Your correct option is A.

3 0

3 years ago

Read 2 more answers

What is the total cost of a $12.50 item plus 6% sales tax?

o-na [289]

6% = 0.06

The total cost of a $12.50 item plus 6% sales tax :

$12.50 * 1.06 = $13.25

Answer

$13.25

5 0

4 years ago

Find the work required to move an object in the force field F = ex+y <1,1,z> along the straight line from A(0,0,0) to B(-1

storchak [24]

Answer:

Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field

$\large F(x,y,z)=(e^{x+y},e^{x+y},ze^{x+y})$

along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

Given two points P, Q in any euclidean space, you can always parameterize the segment of line that goes from P to Q with

r(t) = tQ + (1-t)P with 0 ≤ t ≤ 1

r(t) = t(-1,2,-5) + (1-t)(0,0,0) = (-t, 2t, -5t) with 0≤ t ≤ 1

is a parameterization of the segment.

the work W required to move an object in the force field F along the straight line from A to B is the line integral

$\large W=\int_{C}Fdr$

where C is the segment that goes from A to B.

$\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt$

Integrating by parts the last integral:

$\large \int_{0}^{1}te^tdt=e-\int_{0}^{1}e^tdt=e-(e-1)=1$

and

$\large \boxed{W=\int_{C}Fdr=e+24}$

To show that F is not conservative, we could find another path D from A to B such that the work to move the particle from A to B along D is different to e+24

Now, let D be the path consisting on the segment that goes from A to (1,0,0) and then the segment from (1,0,0) to B.

The segment that goes from A to (1,0,0) can be parameterized as

r(t) = (t,0,0) with 0≤ t ≤ 1

so the work required to move the particle from A to (1,0,0) is

$\large \int_{0}^{1}(e^t,e^t,0)\circ (1,0,0)dt =\int_{0}^{1}e^tdt=e-1$

The segment that goes from (1,0,0) to B can be parameterized as

r(t) = (1-2t,2t,-5t) with 0≤ t ≤ 1

so the work required to move the particle from (1,0,0) to B is

$\large \int_{0}^{1}(e,e,-5et)\circ (-2,2,-5)dt =25e\int_{0}^{1}tdt=\frac{25e}{2}$

Hence, the work required to move the particle from A to B along D is

e - 1 + (25e)/2 = (27e)/2 -1

since this result differs from e+24, the force field F is not conservative.

6 0

4 years ago

3x2 = 75 - Find the value of x.

Zielflug [23.3K]

First Simplify the numbers we know. Therefore we get: x2=75/3 which is the same as x2=25

Now find the square root of 25, which is 5 or -5. Therefore x=5 or -5

7 0

2 years ago

Read 2 more answers