A.Rhombus and D.Square
Hope this helps <3
The mistakes that were made regarding the transformation are:
- He applied the reflection to the pre-image first.
- He used an incorrect angle of rotation around point P
<h3>How to illustrate the information?</h3>
It should be noted that a transformation simply means the changing of the position of an object
In this case, the transformation is incorrect as he applied the reflection to the pre-image first and used an incorrect angle of rotation around point P.
Learn more about transformation on:
brainly.com/question/14911648
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Answer:
Inverse Function: f^-1(x) = 9/4x + 9
Step-by-step explanation:
To find the inverse function we can interchange the position of the variables x and y, and then solve for y;
y = 4/9x - 4 => x = 4/9y - 4,
x = 4/9y - 4,
4/9y = x + 4,
y = 9/4x + 9/4(4),
y = 9/4x + 9/ f^-1(x) = 9/4x + 9
Answer:
X >>>>> Y
–1 >>>> 16
0 >>>>> 8
1 >>>>> 4
2 >>>>> 2
3 >>>>> 1
Step-by-step explanation:
From the question given above,
y = 8 × (½)ˣ
When x = –1, y =?
y = 8 × (½)ˣ
y = 8 × (½)¯¹
y = 8 × 2
y = 16
When x = 1, y =?
y = 8 × (½)ˣ
y = 8 × (½)¹
y = 8 × ½
y = 4
When x = 2, y =?
y = 8 × (½)ˣ
y = 8 × (½)²
y = 8 × ¼
y = 2
When x = 3, y =?
y = 8 × (½)ˣ
y = 8 × (½)³
y = 8 × ⅛
y = 1
SUMMARY:
X >>>>> Y
–1 >>>> 16
0 >>>>> 8
1 >>>>> 4
2 >>>>> 2
3 >>>>> 1
Triangular sequence = n(n + 1)/2
If 630 is a triangular number, then:
n(n + 1)/2 = 630
Then n should be a positive whole number if 630 is a triangular number.
n(n + 1)/2 = 630
n(n + 1) = 2*630
n(n + 1) = 1260
n² + n = 1260
n² + n - 1260 = 0
By trial an error note that 1260 = 35 * 36
n² + n - 1260 = 0
Replace n with 36n - 35n
n² + 36n - 35n - 1260 = 0
n(n + 36) - 35(n + 36) = 0
(n + 36)(n - 35) = 0
n + 36 = 0 or n - 35 = 0
n = 0 - 36, or n = 0 + 35
n = -36, or 35
n can not be negative.
n = 35 is valid.
Since n is a positive whole number, that means 630 is a triangular number.
So the answer is True.
