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2 years ago

18.5 ft, 6 ft, 17.5 ft

Mathematics

2 answers:

Julli [10]2 years ago

8 0

What is the question?

pishuonlain [190]2 years ago

8 0

Answer:

yes, it is a right triangle.

Step-by-step explanation:

you could use the pythagorean theory to check:

$a^{2} + b^{2} = c^{2}$

(the hypotenuse is the longest side)

$17.5^{2} + 6^{2} = 18.5^{2}$

$306.25 + 36 = 342.25$

$342.25 = 342.25$

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The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665 Using a table of values,

vladimir1956 [14]

Answer:

There are 5 terms in the series.

Step-by-step explanation:

$S=a\frac{1-r^{n} }{1-r}\\a=-3\\r=6\\-4665=-3\frac{1-6^{n} }{1-6}\\1555=\frac{1-6^{n} }{-5}\\\-7775=1-6^{n}\\6^{n}=7776\\$

Take logs to get n = 5

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3 years ago

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never [62]

Answer:

Step-by-step explanation:

The tuna can has a shape of a cylinder, and the area of the tuna lablel is the lateral surface area of the can

$A=2\pi rh$

Data

diameter d= 6.5cm

radius r = $\frac{diameter}{2}$ = $\frac{6.5}{2} = 3.25cm$

height h= 3cm

leteral surface area

$A=2*3.142*3.25*3\\= 61.269\\=61.27cm^2$

3 0

2 years ago

Katrina drinks 0.5 gallons of water per day. Which expression shows how to find the number of cups of water she drinks in a

Hunter-Best [27]

Answer:

Well the options are not copy pasted properly so im just gonna answer the question

Step-by-step explanation:

1 Gallon contains 16 cups,

so 16 cups for 1 day

so for 7 days,

No. of cups = 7 x 16 = 112

so the expression would be,

16 cups x 7 days

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2 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

2 years ago

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Bogdan [553]

Answer:

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Step-by-step explanation:

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2 years ago

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