Solve for x using Logarithm4^x+6^x =9^x
1 answer:
4^x + 6^x = 9^x
4^x + 6^x - 9^x = 0
2^2x + (2×3)^x - 3^2x = 0
2^2x + 2^x×3^x - 3^2x = 0
(⅔)^2x + (⅔)^x - 1 = 0
let t = ( ⅔)^x
t² + t - 1 = 0
t = (-1+√5 ) / 2
(⅔)^x = (-1+√5 ) / 2
x = Log base ⅔ ((-1+√5 ) / 2 )
x = 1.18681
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