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kaheart [24]
3 years ago
5

What are the domain and range of the function f(x)=|x-5| + 10

Mathematics
1 answer:
adell [148]3 years ago
8 0
Hi eue was your day you were gone and you did a good night
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Write the equation of a horizontal line that passes through the point (3,-3).
cestrela7 [59]
Hello : 
 the equation is : y -(-3) = 0(x-3)....(slope = 0 '<span>horizontal line')
y=-3</span>
4 0
3 years ago
A certain new type of business succeeds 60% of the time. Suppose that 3 such businesses open (where they do not compete with eac
ella [17]

Answer:

0.216

Step-by-step explanation:

Given that a certain new type of business succeeds 60% of the time.

3 such businesses   are tested for success.

Since these three businesses open (where they do not compete with each other, so it is reasonable to believe that their relative successes would be independent). we can say X no of successful businesses is Binomial

with p = 0.6 and n =3

Required probability

=The probability that all 3 businesses succeed is:

= P(X=3)\\= 0.6^3\\= 0.216

8 0
3 years ago
after a party, you have 2/5 of the brownies you made left over. there are 16 left. how many brownies did you make for the party
vodomira [7]
16 = 2/5
16 ÷ 2 = 2/5 ÷ 2/1
8 = 1/5
8 * 5 = 1/5 * 5
40 = 5/5
You started the party with 40 brownies
7 0
3 years ago
Read 2 more answers
Subtract: (x^2 - 8x + 5)-(-3x^2 + 5x-9)
Marianna [84]

Answer: 4x^2 -13x + 14

Step-by-step explanation:

(x^2 - 8x + 5)-(-3x^2 + 5x-9)

Subtract -3x^2 from x^2

(4x^2 - 8x + 5)-(5x-9)

Subtract 5x from -8x

(4x^2 -13x + 5)-(-9)

Subtract 9 from 5

4x^2 -13x + 14

7 0
3 years ago
To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
vlada-n [284]
<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
8 0
2 years ago
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