or
Answer:
Solution given:
y=2x²-5x+6.....[1]
y=3x+3.........….[2]
solving equation 1&2
2x²-5x+6=3x+3
2x²-5x-3x+6-3=0
2x²-8x+3=0
comparing above equation with ax²+bx+c=0 we get
a=2
b=-8
c=3
by using quadratic equation
taking positive
taking negative
An art school charges a materials fee in addition to a fee per class. The equation below represents the total cost y of
1 answer:
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Step-by-step explanation:
x^3 is a perfect cube, 8 is a perfect cube, so we use difference of cubes.
Cube root of x^3 is x.
Cube root of 8 is 2
So
a=x
b= 2.
Set these equations equal to zero
If we do the discriminant, we get a negative answer so we would have two imaginary solutions,
Thus the only real root is 2.
If you want imaginary solutions, apply the quadratic formula.
and