Answer:
c. 61.25 kg
Step-by-step explanation:
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.
a. 15.31 kg
b. 51.40 kg
c. 61.25 kg
d. 80.49 kg
Margin of Error Formula= z × Standard deviation/√n
95% confidence interval = 1.96
Standard deviation = 125kg
n = 16 samples
Margin of error= 1.96 × 125/√16
= 1.96 × 125/4
= 245/4
= 61.25kg
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg
Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40.
From there use algebraic steps to find out what x is ( the break - even point ).
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40
0.855625x - 4x + 20 = 1.265625x + 6x + 40
-0.41x - 4x + 20 = 6x + 40
-4.41x + 20 = 6x + 40
20 = 10.41x + 40
-20 = 10.41x
-1.92122958694 = x
Rounded to the nearest tenth it's -1.9 = x.
Tell me if I got something wrong :)
Answer:
C. 40in
Step-by-step explanation:
so...
576+1024=1600
the missing side = 40in
So if they eat 450 lb a day and you have a 3600 lb supply you simply divide 3600 by 450.
3600/450=8 days
so your final answer is 8 days.
Answer:
Step-by-step explanation:
20.70/90= 0.23 per foot
30*.23= 6.90
It'll cost $6.90 for 30 more feet.
