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koban [17]
3 years ago
12

HELP WITH THIS QUESTION PLS

Mathematics
1 answer:
umka21 [38]3 years ago
8 0

Answer:

Step-by-step explanation:

                  Statements                                   Reasons

1). ∠CXY ≅ ∠BXY                             1). Given

2). ∠CAX ≅ ∠BAX                            2). Given

3). AC ≅ AB                                      3). Given

4). AX ≅ AX                                      4). Reflexive property

5). ΔAXC ≅ ΔAXB                            5). SAS property of congruence

6). CX ≅ BX                                      6). CPCTC

7). XY ≅ XY                                       7). Reflexive property

8). ΔYXB ≅ ΔYXC                             8). SAS property of congruence

9). ∠XCY ≅ ∠XBY                             9). CPCTC  

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I need to figure out if I'm doing this correctly
kogti [31]

To prove that triangles TRS and SUT are congruent we can follow these statements:

1.- SR is perpendicular to RT: Given

2.-TU is perpendicular to US: Given

3.-Angle STR is congruent with angle TSU: Given.

4.-Reflexive property over ST: ST is congruent with itself (ST = ST)

From here, we can see that both triangles TRS and SUT have one angle of 90 degrees, another angle that they both have, and also they share one side (ST) ,then:

5.- By the ASA postulate (angle side angle), triangles TRS and SUT are congruent

5 0
1 year ago
Carlos is driving on a straight section of highway from Ashford to Lincoln. Ashford is at mile marker 333 and Lincoln is at mile
Arte-miy333 [17]

Distance between the two cities:

453 - 333 = 120 miles.

Rest area is 2/3 of the way:

120 x 2/3 = 240/3 = 80 miles.

Divide the miles to the rest stop by his speed:

80 miles/ 60 miles per hour = 1 and 1/3 hours as a fraction. 1.3333 as a decimal( round as needed.

( 1 hour and 20 minutes)

3 0
3 years ago
What is the solution to 4(x-1)-2(3x+5)=-3x-1
Margarita [4]

To solve this problem, we need to get the variable x alone on one side of the equation. To begin, we are going to use the distributive property twice on the left side of the equation to expand the multiplication and get rid of the parentheses.

4(x-1) - 2(3x + 5) = -3x -1

4x - 4 -6x - 10 = -3x - 1

Next, we should combine like terms on the left side of the equation. This means we should add/subtract the variable terms and the constant terms in order to simplify this equation further.

-2x - 14 = -3x - 1

Then, we have to add 3x to both sides of the equation to get the variable terms all on the left side of the equation.

x - 14 = -1

After that, we should add 14 to both sides of the equation to get the variable x alone one the left side of the equation.

x = 13

Therefore, the answer is 13.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Need help ASAP. Last two problems on my study guide, can't seem to solve them?
Dimas [21]

Answer:

9) 4

10) p¹⁵/q⁹        

Step-by-step explanation:

9)

As per the law of indices, (xᵃ)ᵇ=xᵃᵇ.

So divide 8 by 2 to get 4

10)

p(p⁻⁷q³)⁻²q⁻³

p(p¹⁴q⁻⁶)q⁻³       <em>(because (xᵃ)ᵇ=xᵃᵇ)</em>

pq⁻³(p¹⁴q⁻⁶)

p¹⁵q⁻⁹

p¹⁵/q⁹                <em>(because x⁻ᵃ =1 /xᵃ)</em>

4 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
kompoz [17]

Answer:

K(-4,8) is the ortho center.

Step-by-step explanation:

In a right angled triangle, The vertex of the right angle is the ortho center.

Here we are given

J(-4,-1), K(-4,8) & L(2,8)

Using distance formula we get

JK^{2}= (-4+4)^{2}+ (8+1)^{2}=0+81=81

KL^{2}= (-4-2)^{2}+ (8+-8)^{2}=36+0=36

JL^{2}= (-4-2)^{2}+ (8+1)^{2}=36+81=117

So we can say that

JK^2 + KL^2=JL^2

By converse of pythagorean theorem we get

Hence the Vertex of the right angle is K(-4,8)

K(-4,8) is the ortho center.

7 0
3 years ago
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