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emmasim [6.3K]
2 years ago
8

1. How many tiles would be in Figure 5?*

Mathematics
1 answer:
Alex777 [14]2 years ago
4 0

Answer:

Hi am from India.

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Step-by-step explanation:

please mark me as brainliest.

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How do if-then statements describe mathematical relationships?
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Answer:

Hypotheses followed by a conclusion is called an statement conditional statement. This is read - if then . A conditional statement is false if hypothesis is true and the conclusion is false. ... If we re- arrange conditional statement or change parts of then we have what is called a related conditional .

3 0
3 years ago
Find the value of the variable if P is between J & K. A) JP = 8z - 17 B) PK = 5z + 37 C) JK = 17z - 4
Daniel [21]
<span>We cannot deduce about the exact location of P between J and K. But we can conclude: segment JP + segment PK = line JK.
</span><span>JP + PK = JK.
</span><span>Substitute first each.
(8z - 17) + (5z + 37) = 17z - 4
Combine like terms.
13z + 20 = 17z - 4
Isolate the variable z.
4z = 24
z = 6
The value of the variable z is then 6 units.</span>
3 0
3 years ago
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Is the following shape a square? How do you know
swat32
Yes, they all have 4 corners.
3 0
2 years ago
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Solve.<br><br> The answer must be a fraction. Solve by substituting.
maw [93]

Answer: x = -14/5

Step-by-step explanation: We shall begin by expanding the brackets for both sides of the equation

-2/3 (x + 2) = 1/6 (x + 6)

(-2x/3) -4/3 = (x/6) + 1

By collecting like terms we now have

(-2x/3) - (x/6) = 1 + 4/3

(-4x - x)/6 = 7/3

-5x/6 = 7/3

By cross multiplication we now have

-5x (3) = 7 (6)

-15x = 42

x = -(42/15) {simplify further by dividing the RHS by 3}

x = -14/5

Therefore x equals, minus fourteen over five (-14/5)

4 0
3 years ago
Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\&#10;\mathsf{5^2\,cos^2\,\theta=4^2}\\\\&#10;\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\&#10;\mathsf{25-16=25\,sin^2\,\theta}\\\\&#10;\mathsf{9=25\,sin^2\,\theta}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{9}{25}}&#10;

\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\&#10;\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
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