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3 years ago

In need of help thanks

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

6 0

Answer:

x = 20

y = 25

z = 24

Step-by-step explanation:

2y + 10 = 60

2y = 50

y = 25

2y + 10 = 3x

but y = 25

=> 50 + 10 = 3x

3x = 60

x = 20

5z + 3x = 180

but x = 20

5z + 60 = 180

5z = 120

z = 24

please give me brainlist if it is helpful for you

pogonyaev3 years ago

4 0

Step-by-step explanation:

x = 20

y = 25

z = 24

plz mark my answer as brainlist plzzzz vote me also.

hope this will be helpful to you .

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The distance traveled by a certain vehicle varies directly to the amount of fuel the vehicle consumes. The vehicle traveled 90 m

olga_2 [115]

Answer:

The vehicle covers 126 miles on 7 gallons of fuel.

Step-by-step explanation:

Given:

The distance traveled is directly proportional to the amount of fuel.

For $F$ gallons of fuel distance traveled $D$ miles can be given as:

$D$ ∝ $F$

$D=kF$

where $k$ is constant of proportionality.

The vehicle covers $D=90$ miles on $F=5$ gallons.

$90=k(5)$

Dividing both sides by 5.

$\frac{90}{5}=\frac{k(5)}{5}$

$18=k$

∴ $k=18$

When $F=7$ gallons

$D=(18)(7)$

$D=126$ miles

∴ The vehicle covers 126 miles on 7 gallons of fuel.

4 0

3 years ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$