3 years ago

What is the difference of 1/5 - 3/4

Mathematics

1 answer:

stira [4]3 years ago

7 0

Answer:

1/5 and 3/4 difference is —

-11/20

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Factor each expression 31

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You can’t factor 31 since it’s a prime number luv

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When seven is subtracted from half of a number, the result is negative three. Find the number

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

0.5x-7=3

add 7 to both sides

0.5x=4

multiply both sides by 2

x=8

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3 years ago

How can you determine if a relation is a function?

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cause none of the x's will repeat

Step-by-step explanation:

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3 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of years that the time could be read at night is 30.4 years.

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3 years ago

9+g+6g–3 a n s w e r p l e a s e

Alex_Xolod [135]

If you are being asked to simplify, just combine like terms; such as, all the g’s and all the numbers so, your answer should look something like: 7g+6

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2 years ago

Read 2 more answers