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tigry1 [53]
3 years ago
9

What is the volume of the cylinder below?

Mathematics
2 answers:
taurus [48]3 years ago
6 0
The answer would be A
melamori03 [73]3 years ago
3 0

Answer:

A. 7847 units3

Step-by-step explanation:

just answeres this question

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Help ASAP please help me out with the question
aev [14]

Answer:

x=5x66=300

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Evaluate the function<br> f(x)= 7.45x + 33.7 at x= -4.3
slavikrds [6]
First, you have to substitute for x, which would make the problem f(x)=7.45(-4.3)+33.7
Now, you just have to use the PEMDAS method (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
f(x)= -32.035+33.7
f(x)=1.665
6 0
3 years ago
Question 2 (Essay Worth 10 points)
icang [17]

Answer:

Part A: 1 solution

Part B:

3(2x-7)=3

6x-21=3

 +21  +21

6x=24

/6    /6

x=4

Step-by-step explanation:

First you <u>distribute 3(2x-7)=3</u> to 6x-21=3. Next you do inverse operations by <u>adding 21 to both sides</u> of the equation to get 6x=24. Finally you <u>divide both sides by 6</u> to get x=4

7 0
3 years ago
If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
3 years ago
AnsweR quickkkkkKkkkkkk
Papessa [141]

Answer:

A & E

Step-by-step explanation:

_________________

4 0
3 years ago
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